Logarithm Addition

Algebra Level 3

Let K K be equal to the following expression. What is 201 4 K ? 2014^K? K = n = 2 2014 1 log n 2014 K=\sum_{n=2}^{2014}\dfrac{1}{\log_n2014}

2014 ! 2014! 201 4 2014 2014^{2014} 1 1 2014 2014

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1 solution

Anish Puthuraya
Mar 6, 2014

Note that,
1 log n 2014 = log 2014 n \frac{1}{\log_{n} 2014} = \log_{2014}n

Thus,
K = n = 2 2014 log 2014 n K = \sum_{n=2}^{2014}\log_{2014}n

K = log 2014 2 + log 2014 3 + + log 2014 2014 K = \log_{2014}2 + \log_{2014}3+\ldots+\log_{2014}2014

K = log 2014 ( 2 × 3 × 4 × × 2014 ) K = \log_{2014}(2\times 3\times 4\times\ldots\times 2014)

K = log 2014 2014 ! K = \log_{2014}2014!

Therefore,
201 4 K = 201 4 log 2014 2014 ! = 2014 ! 2014^K = 2014^{\log_{2014}2014!} = \boxed{2014!}

thanks for an elegant solution "anish puthuraya"

Rishabh Jain - 7 years, 3 months ago

Exactly the solution I was looking for!

Trevor B. - 7 years, 3 months ago

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Are there any other methods to solve the problem? I would love to check them out.

Anish Puthuraya - 7 years, 3 months ago

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Yours is the one I had in mind. I don't think there is another way to do it. The trick is to justify that 1 log a b = log b a \frac{1}{\log_ab}=\log_ba for a , b 1 a,b\neq1 . For completion's sake, can you figure out how to do this?

Trevor B. - 7 years, 3 months ago

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@Trevor B. Well, it is pretty straightforward.

Let log a b = k \displaystyle\log_ab = k (say)

Then,
b = a k b = a^k

b 1 k = a \Rightarrow b^{\frac{1}{k}} = a

Taking log \displaystyle\log to the base b \displaystyle b on both sides,

1 k = log b a \Rightarrow \frac{1}{k} = \log_ba

Re-substituting the value of k \displaystyle k , we get,

1 log a b = log b a \frac{1}{\log_ab} = \log_ba

Hence, Proved.

Anish Puthuraya - 7 years, 3 months ago

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@Anish Puthuraya Very good! Personally, I would say this.

1 log a b × log b a log b a = log b a log a b × log b a = log b a 1 = log b a \dfrac{1}{\log_ab}\times\dfrac{\log_ba}{\log_ba}=\dfrac{\log_ba}{\log_ab\times\log_ba}=\dfrac{\log_ba}{1}=\log_ba

You can use change of base to prove that log a b × log b a = 1 , \log_ab\times\log_ba=1, as I discussed in a note I created a couple weeks ago.

Trevor B. - 7 years, 3 months ago

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@Trevor B. Yeah, that's pretty good too.

Anish Puthuraya - 7 years, 3 months ago

correct

Maya Patil - 7 years, 2 months ago

How did the final answer come from the previous step? Please...

Ashley Shamidha - 7 years ago

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since a^log a b = b Therefore 2014^log 2014! equals 2014!

Huey Chan - 7 years ago

what does this ! mean?

Rahul Shah - 6 years, 11 months ago

I had the same solution but I voted up this not to watse time

Govind Balaji - 6 years, 9 months ago

Expression for K is to be found . Not of 2014^ K

prasad mahadik - 5 years, 8 months ago

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