Logarithms' challenger #3

Algebra Level 2

x log x + 5 3 = 1 0 5 + log x \large{x^{\dfrac{\log x+5}{3}}=10^{5+\log x}}

Find the value of x x satisfying the below equation above where x x is an integer.


This problem is a part of this set .


The answer is 1000.

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4 solutions

Akhil Bansal
Oct 10, 2015

Its a one line question,
Suppose log 10 x + 5 = k \log_{10} x + 5 = k

x k / 3 = 1 0 k x = 1000 \Rightarrow \large x^{k/3} = 10^k \Rightarrow \color{#3D99F6}{\boxed{x = 1000}}

Same method

I think I need not post the same solution again.(just joking)

Rama Devi - 5 years, 2 months ago
Raj Rajput
Oct 10, 2015

@rohit udaiwal edit your problem as x is an integer :)

RAJ RAJPUT - 5 years, 8 months ago

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Thanks for notifying:P

Rohit Udaiwal - 5 years, 8 months ago

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Can you explain me this one?

Abhiram Rao - 5 years, 2 months ago

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@Abhiram Rao Which step(s) is troubling you?I would love to help you :D Also, you may want to read this .

Rohit Udaiwal - 5 years, 2 months ago

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@Rohit Udaiwal Done! Thanks :D

Abhiram Rao - 5 years, 2 months ago

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@Abhiram Rao Great!It's awesome to see a genius 8 grader like you solving such problems!BTW do you like the set?It was my first ever set so I'm always kinda excited about it:P

Rohit Udaiwal - 5 years, 2 months ago

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@Rohit Udaiwal Interesting :D

Abhiram Rao - 5 years, 2 months ago
Aakash Khandelwal
Oct 13, 2015

Take log on both sides and approach a quadratic .

Sai Aryanreddy
Oct 11, 2015

Ur in DSNR?

Abhiram Rao - 5 years, 2 months ago

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