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Algebra Level 4

( ln x ) 2 3 ln x + 3 ln x 1 < 1 \frac{(\ln x)^2-3\ln x+3}{\ln x-1}<1

If x x satisfy the inequality above, then find the domain of x x .

For more questions on logarithms try this set Logs of logs .
( 1 , 2 e ) (1,2e) ( 0 , e ) (0,e) No solution ( 0 , 3 e ) (0,3e) ( 1 , e ) (1,-e)

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1 solution

Yash Choudhary
Apr 5, 2015

( l n x ) 2 3 l n x + 3 l n x 1 < 1 L e t l n x b e t , t 2 3 t + 3 t 1 < 1 t 2 4 t + 4 t 1 < 0 ( t 2 ) 2 t 1 < 0 t ( , 1 ) l n x < 1 x > 0 a n d x < e x ( 0 , e ) . \Rightarrow \quad \frac { (lnx)^{ 2 }-3lnx+3 }{ lnx-1 } <1\\ Let\quad lnx\quad be\quad t,\\ \Rightarrow \quad \frac { { t }^{ 2 }-3t+3 }{ t-1 } <1\\ \Rightarrow \quad \frac { { t }^{ 2 }-4t+4 }{ t-1 } <0\\ \Rightarrow \quad \frac { { (t-2) }^{ 2 } }{ t-1 } <0\\ \therefore \quad t\in (-\infty ,1)\\ \Rightarrow \quad lnx<1\\ \Rightarrow \quad x>0\quad and\quad x<e\\ \therefore \quad \boxed { x\in (0,e) } .

Why are questions in my set rated level 5 and all are above 245 pts.They are very easy.I thought that they would be level 2 or3. But i know there level decrease after some time. Nice solution.

Gautam Sharma - 6 years, 2 months ago

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See now its level 2. :P

Yash Choudhary - 6 years, 2 months ago

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If u r looking for something tough try this

Tanishq Varshney - 6 years, 2 months ago

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@Tanishq Varshney Nice problem.

Yash Choudhary - 6 years, 2 months ago

Same solution :D

Paul Ryan Longhas - 6 years, 2 months ago

over rated problem

Tanishq Varshney - 6 years, 2 months ago

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