Consider a long current carrying cylindrical conductor of radius
Current density
inside the conductor is uniform over its cross-section.
Deduce suitable expression for force of interaction per unit length
between two halves that are obtained by dividing the conductor by a
plane containing the axis of the conductor.
Answer comes in the form of Type your answer as
The problem is taken from my Physics Book.
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Nice problem. The infinitesimal current element is:
d I = ( 0 , 0 , j r d r d θ )
The scalar magnetic flux density at radius r is (by convention, I consider R to be the total radius):.
B = 2 π r μ 0 I e n c l o s e d = 2 π r μ 0 j π r 2 = 2 μ 0 r j
The vector magnetic flux density is:
B = ( − 2 μ 0 r j sin θ , 2 μ 0 r j cos θ , 0 )
The infinitesimal flux contribution per unit length is:
d F = d I × B = ( − 2 μ 0 r 2 j 2 cos θ d r d θ , 2 μ 0 r 2 j 2 sin θ d r d θ , 0 )
Only the y force evaluates to a non-zero net value value over the range ( 0 ≤ θ ≤ π ) . Evaluating the y force over the half circle ( y ≥ 0 ) results in:
F y = ∫ 0 π ∫ 0 R 2 μ 0 r 2 j 2 sin θ d r d θ = 3 1 μ 0 j 2 R 3