Magnitude

Calculus Level 5

I draw a vector r 1 \vec{r_{1}} in the plane, and a vector r 2 \vec{r_{2}} orthogonal to r 1 \vec{r_{1}} . Their resultant vector is then R 1 \vec{R_{1}} .

Then, I draw a vector r 3 \vec{r_{3}} orthogonal to R 1 \vec{R_{1}} with their resultant being R 2 \vec{R_{2}} .

Following this pattern, I keep on drawing vectors and resultants ad infinitum.

If r n r 1 = 1 n \frac{|\vec{r_{n}}|}{|\vec{r_{1}}|} = \frac{1}{n} for all n 1 n \geq 1 and R = π |\vec{R_{\infty}}| = \pi , find the dot product of r 1 \vec{r_{1}} with itself.


The answer is 6.

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1 solution

Jake Lai
Jan 30, 2015

We know that

R = r 1 2 + r 2 2 + r 3 2 + = r 1 k = 1 1 k 2 = π |\vec{R_{\infty}}| = \sqrt{|\vec{r_{1}}|^{2}+|\vec{r_{2}}|^{2}+|\vec{r_{3}}|^{2}+\ldots} = |\vec{r_{1}}|\sqrt{\sum_{k=1}^{\infty} \frac{1}{k^{2}}} = \pi

Since we know r 1 k = 1 1 k 2 = r 1 π 2 6 = π \displaystyle |\vec{r_{1}}|\sqrt{\sum_{k=1}^{\infty} \frac{1}{k^{2}}} = |\vec{r_{1}}|\sqrt{\frac{\pi^{2}}{6}} = \pi , it follows that

r 1 r 1 = r 1 2 = 6 \vec{r_{1}} \cdot \vec{r_{1}} = |\vec{r_{1}}|^{2} = \boxed{6}

When the problem says R = π \vec{R_{\infty}} = \pi , it should say R = π |\vec{R_{\infty}}| = \pi .

Jon Haussmann - 6 years, 4 months ago

Hi , good question , should get at least a Level 4 rating . And thanks for the proof of k = 1 1 k 2 = π 2 6 \sum_{k=1}^{\infty} \frac{1}{k^{2}} = \frac{\pi^{2}}{6} , as I used wolfram Alpha to evaluate the sum .

Also I have a doubt , what's the difference between using () and [] in LaTEX ?

Thanks for the same .

A Former Brilliant Member - 6 years, 4 months ago

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() does not center your LaTeX, but [] does (and creates a new line for the maths). The former is useful for inserting just small, not-so-important statements/terms/etc, whereas the latter shows your steps more clearly.

Jake Lai - 6 years, 4 months ago

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Thanks and keep posting such good questions .

A Former Brilliant Member - 6 years, 4 months ago

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@A Former Brilliant Member You're welcome! Happy solving.

Jake Lai - 6 years, 4 months ago

kinda overrated now...

Julian Poon - 6 years, 4 months ago

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In retrospect, I should have made this a level 4.

Jake Lai - 6 years, 4 months ago

Good use of the Basel Problem.

Aakarshit Uppal - 6 years, 4 months ago

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