Foolish invertible g(x) !!

Calculus Level 5

1 x 4 7 g ( x ) e ln ( f ( sin 2 t ) cos 2 t ) d t = 1 x 7 4 1 x 4 7 \large \int _{ \sqrt [ 7 ]{ 1-{ x }^{ 4 } } }^{ g\left( x \right) }{ { e }^{ \ln (f (\sin ^{ 2 }{ t } ) \cos ^{ 2 }{ t ) } } } dt =\sqrt [ 4 ]{ 1-{ x }^{ 7 } } -\sqrt [ 7 ]{ 1-{ x }^{ 4 } }

For the equation given above, where g ( x ) = 1 x 7 4 g \left( x \right) =\sqrt [ 4 ]{ 1-{ x }^{ 7 } } is an invertible function, find f ( 1 2 ) f ( 1 3 ) f \left(\frac 12\right)\cdot f \left(\frac 13\right) .


This is part of the set Foolish Things


The answer is 3.

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1 solution

Deepanshu Gupta
Oct 1, 2014

F i r s t t h i n g t h a t s t r i k e i n m i n d t o d o q u e s t i o n i s b y u s i n g L e i b n i t z T h e o r a m . . . B u t P l z a v o i d i t h e r e L e t s d o s o m e d i f f r e n t . . . . : N o t e T h a t : a b 1. d x = b a s o a c c o r d i n g t o q u e s t i o n e l n ( f ( s i n 2 t ) c o s 2 t = 1 f ( s i n 2 t ) c o s 2 t = 1 f ( s i n 2 t ) = 1 c o s 2 t = 1 1 s i n 2 t f ( x ) = 1 1 x x [ 1 , 1 ] f ( 1 / 2 ) . f ( 1 / 3 ) = 3 A n s . First\quad thing\quad that\quad strike\quad in\quad mind\quad to\quad do\quad question\quad is\\ by\quad using\quad Leibnitz\quad Theoram...But\quad Plz\quad avoid\quad it\quad here\\ Let's\quad do\quad some\quad diffrent....\quad :\\ Note\quad That\quad :\quad \\ \int _{ a }^{ b }{ 1.dx } =b-a\\ so\quad according\quad to\quad question\quad \\ \Longrightarrow \quad { e }^{ ln(f(sin^{ 2 }{ t) }cos^{ 2 }{ t } }=1\\ \Longrightarrow \quad f(sin^{ 2 }{ t) }cos^{ 2 }{ t }=1\\ \Longrightarrow \quad f(sin^{ 2 }{ t) }=\frac { 1 }{ cos^{ 2 }{ t } } =\frac { 1 }{ 1-sin^{ 2 }t } \\ \\ \Longrightarrow f\left( x \right) =\frac { 1 }{ 1-x } \quad \forall \quad x\quad \in \quad \left[ -1,1 \right] \\ \\ \longrightarrow \quad f(1/2).f(1/3)=3\quad Ans. .

Fabulous solution....!!! I'm Really Foolish since I use Leibniz Theorem ..!! Nice question

Karan Shekhawat - 6 years, 8 months ago

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But u said CBSE is foolish. Which means ur are CBSE .. HAHA

Ayaen Shukla - 3 years, 1 month ago

good job dude!!

Akshay Bhatia - 6 years, 7 months ago

i did the exact thing,, even posted solution like 10 hours ago,, but accidently pressed keep private button,, and i do not know how to undo it,, i can see it but no one else can

Mvs Saketh - 6 years, 8 months ago

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Sorry Mvs Saketh but i can't see your solution That's why I post my solution. I made this question for only one purpose to solve This question By using This Concept...!!

Deepanshu Gupta - 6 years, 8 months ago

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No i am just telling :) .... either way why did u mention g(x) is an invertible matrix?infact how is it a matrix? Please explain

Mvs Saketh - 6 years, 8 months ago

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@Mvs Saketh ohh..... Typo in question....Thanks For noticing I fixed that.

Deepanshu Gupta - 6 years, 8 months ago

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@Deepanshu Gupta Better would have been if you would have said bijective under certain range.

Ayaen Shukla - 3 years, 1 month ago

Exactly same method used, step by step!

Prince Loomba - 4 years, 7 months ago

yes, the thing why i took a little more time is , i noticed that lower limit is inverse of g ( x ) g(x) and wanted to utilise it but i got a easier way and did just like your solution ! good question bro !

A Former Brilliant Member - 4 years, 6 months ago

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