Map Coloring With Some Already Done

When coloring a map, each region must be filled with a single, solid color and no two regions with touching edges can be the same color.

Given that these two regions have already been colored red, what is the minimum number of colors needed (including the red already used) to color the entire map?

3 4 5 6

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5 solutions

Blan Morrison
Sep 5, 2018

Relevant wiki: Four Color Theorem

We can color the figure normally, apart from the top left region.

There, we run into a problem, because that region is touching 4 other colors, so we need to add a fifth color. Therefore, the minimum number is 5 \boxed{5} .


NOTE : The Four Color Map Theorem (FCMT) states that any blank map has a minimum of four colors. The FCMT doesn't always apply to maps like these. If we were to completely re-color the map to apply to the FCMT, it would look like this:

That's a cunning problem! Since I remember the four color theorem, I only checked if 3 colors are possible and then went for the answer 4. That is doesn't apply due to the fixed red squares really fooled me to act too quickly. Well done.

Manuel Succo - 2 years, 9 months ago

You badly fooled me with a great question. At first glance I expected the trick was going to be that we needed LESS than four colours! At second glance I saw that three were not enough and then fell for it.

Ha ha.

Peter Macgregor - 2 years, 9 months ago

You guys are mistaken. I didn't make the problem; Mr. Dyer, one of the amazing Brilliant staff, did.

Blan Morrison - 2 years, 9 months ago

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I know you didn't, but there's no other way to comment... and anyway, your solution is well written and illustrated. Kudos to that!

Manuel Succo - 2 years, 9 months ago

Correct, the FCMT doesn’t work when someone already started coloring it and expects you to finish. It would be a more interesting question if they asked us to compensate for color blindness.

Brad Stansell - 2 years, 9 months ago

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I really like your thinking, but map coloring allows all 25 6 6 256^6 colors that a computer can generate, and then some. Plus, this is a problem of concreteness, not perspective. However, you could try to find the most complex map that can only be colored with three colors; maybe it could have only one solution.

Blan Morrison - 2 years, 9 months ago

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In that 'minimum' is in the question, my thought process shifted to thinking about a problem of efficiency. My solution was very similar to your FCMT solution except that I left out green (leaving white).

Brad Stansell - 2 years, 9 months ago

Persona 5.... the lesson with the math teacher. Anyone?

Chabo Ster - 2 years, 9 months ago

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Can we please have a relevant discussion about the problem?

Blan Morrison - 2 years, 9 months ago
Stephen Mellor
Sep 8, 2018

First note that every remaining region touches at least one of the red regions, so red cannot be used any more.

Then, notice that each of the numbered regions in the diagram above, touches all of the other 3 numbered regions. This means that 4 unique colours must be used for these regions, as shown. The remaining 2 regions can be coloured any of blue, green or purple (in either order).

Therefore, the total number required is 5 \boxed{5} . This isn't a relevant case of the four colour map theorem as some of the map is already completed.

it is a graph colouring problem where each block represents nodes and connection of blocks represents edges.

atul silori - 2 years, 9 months ago

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That is correct.

Blan Morrison - 2 years, 9 months ago

They never said what else couldnt be done to the map. I simply cut each piece out and solved it with one color and no edges touching the same color

Thor Stambaugh - 2 years, 9 months ago

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I don't understand. If you cut all the pieces out, then the map isn't a map anymore. I believe you don't understand what a map problem is.

Blan Morrison - 2 years, 9 months ago

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If i take a map of the United states, cut out all the states, reassemble them with a small gap between the pieces, it remains a map. It has all the same information and features, and can be used as a map.

Thor Stambaugh - 2 years, 9 months ago

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@Thor Stambaugh This problem is a map in terms of graph theory , not a tourism map.

Blan Morrison - 2 years, 9 months ago

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@Blan Morrison Absolutely, and please point out in the requirements of the question where it says this is disallowed

Thor Stambaugh - 2 years, 9 months ago

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@Thor Stambaugh In a few questions, it is advisable to make sure you've covered every case. For example, in a number theory question, if the problem doesn't specify negative numbers, they can be used and might hold the key to solving the problem. However here, you are being quite frankly ridiculous and trying to change the question until it is beyond meaning. This is just being pedantic, as for this sort of question, it is stupid to try and do such a thing as you are trying. If we all had to cover every loophole in every maths problem ever, it would all be much more complicated and extremely boring.

Stephen Mellor - 2 years, 9 months ago

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@Stephen Mellor Not at all. The joy of these problems is to find a unique solution which still adheres to the parameters set by the question. Granted, some may seem ridiculous, but that is simply the fault of the question. I see a lot of questions here that are easily rigid enough to yield the answer sought and no other. I did not change the question whatsoever. But hey, to each his own. Thank you for your feedback

Thor Stambaugh - 2 years, 9 months ago
Josh Lagerwey
Sep 11, 2018

I look for a region with the most bordering regions. There are four regions bordering another one, so 5 colors are necessary.

I'm afraid your reasoning is not enough. If you concentrate on 1 region with 4 border regions, you can color them using only 3 colors, namely 1 color for the center region and 2 colors for the surrounding ones with the same color for the opposite regions. For example if you look at Stephen Mellor's solution above and concentrate on the green region marked "2". You could color the region marked "1" in red and the one marked "4" in yellow and would need only green, red and yellow. Only if you consider more than the border surrounding region "2" will you notice that this won't work.

Manuel Succo - 2 years, 9 months ago
Nicole Esdaile
Sep 14, 2018

The middle rectangle shares an edge with all of the uncoloured sections so must have it’s own colour. Then, the sections on the right all share edges, so we must have 3 more colours. The final two sections on the left can be coloured with any 2 of the colours in the right section, so we must have 5 colours in total.

Ali Mozayyani
Sep 16, 2018

To solve this, we need to look for neighboring areas (ie areas where a simple bend is connected to other bends) and we need to count the bends that are all connected. If you look at the right half, we have 5 polygons, one of which is red. Apart from the upper polygon, the rest of the polygons are connected to the rest of the polygons, so the color chosen for each polygon should not be used in any of the other polygons, so we need 4 colors. The color that we select for a few upper limits should not be the same with several adjacent gates, and on the other hand, it can not be used in red, because the left is connected to the red polygon so a new color is needed, so a total of 5 colors are needed. The left side can also be filled with right colors because there is no connection to the right side So you need 5 colors in total

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