Mistakes give rise to Problems- 15

Calculus Level 2

If you are given a function y = 19 x 4 13 x 3 + 11 x 2 7 x + 5 \color{#69047E}{y= 19x^4-13x^3+11x^2-7x+5} then we can do it's differentiation as dy dx = 76 x 3 39 x 2 + 22 x 7 \color{#3D99F6}{\dfrac{\textbf{dy}}{\textbf{dx}} = 76x^3-39x^2+22x-7}

If you are given that y = 13 x 3 12 x 2 + 11 x 10 y=13x^3-12x^2+11x-10 then find the answer of dy dt \color{#D61F06}{\dfrac{\textbf{dy}}{\textbf{dt}}}

Details and Assumptions

  • t t is not a monic linear function of x x .
This problem is a part of the set Mistakes give rise to problems
None of these 39 x 2 24 x + 11 39x^2-24x+11 39 x 2 + 24 x 11 39x^2+24x-11 39 x 3 + 24 x 2 + 11 x 10 39x^3+24x^2+11x-10

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1 solution

Aditya Raut
Aug 15, 2014

See that the asked differentiation is in terms of t t , and y y is a function of x x .

Thus the answer of the question is as follows,

d y d t = d y d x d x d t \dfrac{dy}{dt} = \dfrac{dy}{dx} \cdot \dfrac{dx}{dt}

Hence asked thing is d y d t = ( 39 x 2 24 x + 11 ) d x d t \dfrac{dy}{dt} =( 39x^2-24x+11) \dfrac{dx}{dt}

And as t t is not a monic linear function of x x , the value of d x d t \dfrac{dx}{dt} is NOT 1.

Hence the answer is ( 39 x 2 24 x + 11 ) d x d t ( 39x^2-24x+11) \dfrac{dx}{dt} which is not in the options, giving None of these \boxed{\text{None of these}} as the correct answer.

I thought since there is no given relation between x and t hence

d x d t = 0 \frac{dx}{dt}=0 Still I got the right answer.

Ronak Agarwal - 6 years, 10 months ago

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This is not necessary buddy, I only gave that t t is not monic function of x x . This never meant that d x d t = 0 \dfrac{dx}{dt}=0 , that was a trap and luckily your thing worked.

Aditya Raut - 6 years, 10 months ago

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You should try this problem : Let's play pool . I'm sure you will like it.

Ronak Agarwal - 6 years, 10 months ago

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@Ronak Agarwal Good, I suggest you some edits in the LaTeX of the problem.

For the symbol of belongs to , do not use \epsilon .

\epsilon will appear as ϵ \epsilon , the code for belongs to is \in

\in appears as \in

So write it as

y \in (c,d)

which will give output y ( c , d ) y \in (c,d)

Aditya Raut - 6 years, 10 months ago

I misread it as t _is _ a monic function of x.. SHIT!

Pankaj Joshi - 6 years, 9 months ago

Well , that's how i did it.

Keshav Tiwari - 6 years, 10 months ago

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