If you are given a function y = 1 9 x 4 − 1 3 x 3 + 1 1 x 2 − 7 x + 5 then we can do it's differentiation as dx dy = 7 6 x 3 − 3 9 x 2 + 2 2 x − 7
If you are given that y = 1 3 x 3 − 1 2 x 2 + 1 1 x − 1 0 then find the answer of dt dy
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I thought since there is no given relation between x and t hence
d t d x = 0 Still I got the right answer.
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This is not necessary buddy, I only gave that t is not monic function of x . This never meant that d t d x = 0 , that was a trap and luckily your thing worked.
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You should try this problem : Let's play pool . I'm sure you will like it.
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@Ronak Agarwal – Good, I suggest you some edits in the LaTeX of the problem.
For the symbol of belongs to , do not use \epsilon .
\epsilon will appear as ϵ , the code for belongs to is \in
\in appears as ∈
So write it as
y \in (c,d)
which will give output y ∈ ( c , d )
I misread it as t _is _ a monic function of x.. SHIT!
Well , that's how i did it.
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See that the asked differentiation is in terms of t , and y is a function of x .
Thus the answer of the question is as follows,
d t d y = d x d y ⋅ d t d x
Hence asked thing is d t d y = ( 3 9 x 2 − 2 4 x + 1 1 ) d t d x
And as t is not a monic linear function of x , the value of d t d x is NOT 1.
Hence the answer is ( 3 9 x 2 − 2 4 x + 1 1 ) d t d x which is not in the options, giving None of these as the correct answer.