Movie Tickets

Logic Level 1

Which of these options costs less?

(A) Taking 2 friends to the movies once.

(B) Taking 1 friend to the movies twice.

(C) Option A and option B cost the same amount.

Note that all tickets cost the same and you are paying for the tickets.

Image Credit: Wikimedia Larvik, Norge .

A B C None of these choices

12 solutions

Ashwin Padaki
May 7, 2015

You are included in cost. - (2+1) * 1 = 3 and (1+1) * 2 = 4. So 4 > 3

I also second your point. That seems to make even more sense. Mathematics at work! :)

Noel Lo - 6 years, 1 month ago

(A) AND (B) costs two tickets but when we take someone twice the transport cost becomes a extra. (B) is costlier because of more transport costs than (A).

Gourab Roy - 5 years, 10 months ago

No - option A requires 3 tickets (you plus 2 friends). Option B requires 4 tickets (you plus 1 friend, twice).

Steve Ives - 5 years, 6 months ago

Right. I forgot to include the transportation cost

Kenneth Malte - 5 years, 6 months ago

You might walk... You can't assume that there are transportation costs. But if there are, then they make B even more expensive.

Steve Ives - 5 years, 6 months ago

@Steve Ives – so, what do u think? what's right? I may have gentle walk to see the movie via a half mile walk or pay for travelling thousands of miles because for my location, your point makes total sense.So?

Gourab Roy - 5 years, 4 months ago

@Gourab Roy – A is right. Transport costs are not mentioned so you do not include them.

Steve Ives - 5 years, 3 months ago

Not going would cost less. Thus neither is correct

David Rose - 5 years ago

Yep, another clearly wrong answer... (A)(1+2)*1=3 (B)(1+1)+(1+1)=4 4>3: the correct answer is B

Orlando Costa - 5 years, 12 months ago

how?? i could not understand you. please describe.

Harmandeep Singh - 5 years, 10 months ago

Paying for yourself and a movie for your friends once is 3 tickets. Paying for yourself and a single friend twice is 4. Simple math points to be as being the more costly option.

Ethan Czereda - 5 years, 8 months ago

I disagree. The question says take them to the movies. It doesn't indicate you are going into the movie theatre with them. I'd just drop them off.

Keith Scott - 6 years, 1 month ago

If I take u to dinner u think u will be sitting by yourselves alone ?

Werner Van Gelder - 6 years, 1 month ago

It doesn't say "Take two friends to the movies at once." I inferred you are taking two people separately. The verbiage is incomplete.

Timothy Osborne - 6 years ago

Vikram Venkat
May 8, 2015

So basically I included the travel cost also into account. Since going twice is two times going once, and with the current petrol prices, Option A is economically efficient.

I thought of it the same way

Jason Burdett - 6 years, 1 month ago

Well, you see, remember that you're also going to the movies with your friends...

So, You + 1st Friend + 2nd Friend = 3 tickets

But, You + Friend + You + Friend (Twice) = 4 tickets

And as you know 4>3, You have your answer !

Anjushree Verma - 6 years, 1 month ago

Valentshia Lauwrentz Wianata Iii
May 11, 2015

Let's just say the price of ticket is 50 each person.

2 friends + you = 50 + 50 + 50

(1 friend + you) = 50 + 50 | Twice? = 50 + 50 + 50 + 50

There you go ^^

Arbitrary numbers aren't really needed in the explanation but it does work. If you're asked to prove it on some exam such as AIME, then obviously you won't get any points for it.

Timothy Vu - 6 years, 1 month ago

Let the price be 'x' or 'a'

Nghĩa Bùi - 6 years, 1 month ago

Noel Lo
May 10, 2015

For me I did not consider the point that I am also included. I just think that option A is more efficient since you only need to make ONE trip compared to option B where you need to make TWO. Sounds logical too I guess???

Well, you see, remember that you're also going to the movies with your friends...

So, You + 1st Friend + 2nd Friend = 3 tickets

But, You + Friend + You + Friend (Twice) = 4 tickets

And as you know 4>3, You have your answer !

Anjushree Verma - 6 years, 1 month ago

So, me picking the wrong answer is, in fact, wrong. I picked option B. That's the 4 ticket option. Someone needs to fix their question...

Ethan Czereda - 5 years, 8 months ago

Aurora Wang
May 11, 2015

Transportation fees.

a) You + Friend + Friend + car

b) (You + Friend+ 1 car)x2

Nicolas Gosselin
Jun 14, 2016

None of theses choices implies you don't go to the cinema :)

Sharon C Long
Mar 18, 2016

CAN ANYONE EXPLAIN WHAT C MEANS PLEASE? Oh by the way, since i didn't understand C, I ignored it lol so after that, we have A and B. Apparently, one has to pay thrice in scenario A but four times in scenario B, hence A costs less and is the answer.

Nicole Morales
Feb 23, 2016

Option A: Say each ticket is $1 | Yourself + Friend 1 + Friend 2 = $3 Option B: Say each ticket is $1 | Day 1: Yourself + Friend = $2 Day 2: Yourself + Friend = $2 $2 + $2 = $4 Option C: Is not possible since, Option A < Option B or $3 < $4

Conan Stephen
Jan 18, 2016

2 friends plus you is 3 compared with 1 friend plus you is 2 going twice is 4. 3<4 simple

Sadasiva Panicker
Nov 17, 2015

If take 2 persons together, expence for 3 tickets: If one in two times, expence for 4 tickets.

Kevin Chen
Nov 17, 2015

You have to account for your own ticket. If you take 2 friends to the movie once, that's 1 (your ticket) + 2 (your friends' tickets) = 3 tickets total. If you take 1 friend to the movie twice, that's 2 * (1 (your ticket) + 1 (friend's ticket)) = 4 tickets total.

Harvey Dayot
Nov 17, 2015

needed 2 tickets for yourself for 2 movie occasions vs. 1 ticket... same with the snacks and refreshments for yourself... it would be nicer to have.. :) Friend's cost for the 2 scenarios cancel out.

Aside from the obvious 4 tickets vs 3 tickets. There's additional costs of double the transportation, snacks at concession and time. What's 2 extra hours of your time worth?

Kevin Bishop - 5 years, 6 months ago

Movie Tickets

Image Credit: Wikimedia Larvik, Norge .

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