A robot has a wheel and is rotated through a servo (which uses degrees to determine its destination or where to move),the servo is been modified and can move exceeding from 180 º . If its wheel diameter is equal to 10 cm and its present distance reading away from the object is 10 cm. , then what degree of servo will it move to cover up and get into its fix distance of 5 cm.(a distance that the robot should maintain) away from an object if its initial position is 90 degrees?
Note: If there will be a decimal value, then just get to the limit in the hundredths value, or simply round it up.
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first is..will gonna get the difference between the fix distance or the distance that the robot should maintain and the present reading which is 10 cm. , and get its wheel circumference which is equal to
31.4 cm // this is the value of circumference.
10 cm - 5 cm=5 cm
so now to determine the degree, we need to cross multiply it with the following fractions
5/31.4 = _/360 so 5 x 360 = 1800/ 31.4 = 57.32(rounded up) //the exact answer is 57.324840764331210191082802547771
so therefore, if we move the servo by 57.32 degree, then it also covers a distance of 5 cm.
Now, whats being asked on the question is WHAT degree of servo should it move to cover the correct distance. So in this equation, we can get the final answer:
90+57.32= 147.32 degrees
//since we got the initial degree as said in the problem equal to 90 degrees
to check
5 x 360 = 1800 and 31.4 x 57.32 = 1799.848 which can be rounded up = 1800...
:)