As shown in the diagram above, there is a system of 2 charges of opposite signs and equal magnitude Q = 1 μ C , placed over an infinitely extending grounded conductor.
Find the electrostatic potential energy (in Joules) of the system.
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Can you write a solution that is helpful to those who cannot solve it? Else I'm inclined to delete this solution to encourage others to contribute a relevant answer.
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don't u think it's helpful ?
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No, the person who is not able to solve this problem will not be able to understand what is the meaning of "image charge theory" from your solution. Also, it is not clear that how you get the value of potential energy U = − 1 . 8 9 5 . So, it will be really great if you can fill in those gaps and elaborate on it.
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@R G – yes sir, i'll surely do it after physics exam my phone will be repaired by then. i'll upload a pic:)
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@A Former Brilliant Member – Thank you, That will be really helpful for the community.
ok now sir ?
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Yes, I think it is very helpful. Thanks to both of you.
https://goo.gl/photos/cakBycppYXDQH7Qr7 -see my solution here. I was unable to post because i figured it out later after giving wrong answer.
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thnx , u saved me much trouble of repairing my fone :P
Why is the energy being halved??
The level is because many people don't know image charge method as it is not in JEE syllabus , I too myself learnt it some days back!
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Could u post a solution for ur other image theory problme where we needed to find the time to collide
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May be if I can Find time . This is JEE Time.....
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@Aniket Sanghi – Yeah actually! We all learnt it from Youtube!
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Relevant wiki: Conservative nature of Electric fields
uh-oh ! MOTHER of over-rated stuff spotted :P just use image charge theory was getting exactly twice as U i.e -1.895 and half it as the Electric field on the down side of conductor is 0 but while using image charges we calculated electric field for that part also so we have to half our answer by image charges. pic by @Rahul Kumar