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Bài này là bài 446 phần Đại số trong sách Nâng cao và Phát triển Toán 8, tập 2 của Vũ Hữu Bình :D
(No offense) :D
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Bài này là bài cho lớp 6 trên Tạp chí Toán học và Tuổi trẻ tháng 2.
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Lớp 8 nó là bài sao đấy :D
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@Trung Đặng Đoàn Đức – Ừ. Vậy mà cho ng ta cho lớp 6 :v Tớ xem giải trong sách rồi, hay hơn cách của tớ nhỉ? :D
if x=1/2, and y=1, then, min A= 6-5= 1
Is there any method which does not use options? @Aryan Sanghi
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Actually I also did it using options. Also, I am kinda weak in number theory, so I won't be able to tell another solution. :)
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Ok no problem let me ask @Mahdi Raza
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@Vinayak Srivastava – I feel that this method is sufficient to show that 11 is the least difference since the ending digits are cyclic. There was no need to even know the options since there is no other outcome other than 5^y ending in 25 and 36^x ending in 16, 36, 56, 76 or 96. We can see that 36 - 25 is the current minimum, so we just need to check if ( … 3 6 − … 2 5 ) is possible. And the solution has proven that it isn't possible because then 5^y must be div by 3, which isn't possible except y=0, but y>0
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@Mahdi Raza – Nice solution ✌️
@Mahdi Raza – Thanks for the solution!
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