Nested Factorials!

Algebra Level 2

2 ! + 2 ! 2 ! + 2 ! 2 ! + 2 ! 2 ! + \Huge{2!+\frac{2!}{2!+\frac{2!}{2!+\frac{2!}{2!+\ldots}}}} find value of this expression.

1 + 3 1+√3 1 2 1-√2 1 + 2 1+√2 1 3 1-√3

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2 solutions

Sakanksha Deo
Mar 3, 2015

Let,

x = 2 ! + 2 ! 2 ! + 2 ! 2 ! + . . . . . x = 2! + \frac{2!}{2! + \frac{2!}{2! + ..... }}

or,it can be written as,

x = 2 + 2 2 + 2 2 + . . . . x = 2 + \frac{2}{2 + \frac{2}{2 + .... }}

or,

x = 2 + 2 x x = 2 + \frac{2}{x}

or,

x 2 = 2 x + 2 x^{2} = 2x + 2

Now,by using the quadratic formula,

x = 2 + 4 + 8 2 ; 2 4 + 8 2 x = \frac{2 + \sqrt{4 + 8}}{2} ; \frac{2 - \sqrt{4 + 8}}{2}

or,

x = 1 + 3 ; 1 3 x = 1 + \sqrt{3} ; 1 - \sqrt{3}

Now,

Since x x cannot be a negative

Therefore,

x = 1 + 3 x = 1 + \sqrt{3}

Upvoted !!!

A Former Brilliant Member - 6 years, 3 months ago

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Thanx...i guess this is the simpliest way....isn't it

Sakanksha Deo - 6 years, 3 months ago

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That's true......

A Former Brilliant Member - 6 years, 3 months ago

Can anyone please justify why x x cannot be negative ?

Rishabh Tripathi - 6 years, 3 months ago

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Its because all the numbers here are positive.and the sum of positives has to be positive.

Sakanksha Deo - 6 years, 3 months ago

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ohh..kk thats what i was thinking.. you're sure there is no other reason ??

Rishabh Tripathi - 6 years, 3 months ago

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@Rishabh Tripathi No one knows math completely...can have a different reason as welll

Sakanksha Deo - 6 years, 3 months ago

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@Sakanksha Deo yeah true... well Thanks

Rishabh Tripathi - 6 years, 3 months ago

Cannot square root a negative number in the real number system.

Josh Kline - 6 years, 2 months ago

I do not see how the factorials go away on line 3. Can you explain?

Dylan Scupin-Dursema - 6 years, 3 months ago

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Here 2! has been replaced with 2 .
because
2! = 2x1 = 2

A Former Brilliant Member - 6 years, 3 months ago

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Hahaha thank you Pranay.

Dylan Scupin-Dursema - 6 years, 3 months ago

It's easy bro,

n ! = n ( n 1 ) ( n 2 ) ( n 3 ) . . . . . . 3 × 2 × 1 n! = n(n-1)(n-2)(n-3)......3\times2\times1

So,

2 ! = 2 × 1 = 2 2! = 2\times1 = 2

Sakanksha Deo - 6 years, 3 months ago

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Hahah how could I be so silly, thank you Sakanksha.

Dylan Scupin-Dursema - 6 years, 3 months ago

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@Dylan Scupin-Dursema There's no need to thank me......i guess we are here to help each other...isn't it.

Sakanksha Deo - 6 years, 3 months ago

try these questions - QuEsTiOnS

Sakanksha Deo - 6 years, 3 months ago

I did it in the same process !! Simply best process :)

Mahtab Hossain - 6 years, 2 months ago

The above can be rephrased as 2/x+2=x. (If the above expression=x)

Which implies that x 2 {x}^{2} -2x-2=0

Solving we get two roots 1+√3 & 1-√3 As the later is negative the answer is 1+√3

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