If y = 1 + x + 2 ! x 2 + 3 ! x 3 + 4 ! x 4 + . . . , find d x d y .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Obviously this is the expansion serious of e x whose derivative is the function itself... Its good that you mentioned the source of question... Cheers.. (+1)
Log in to reply
Exactly, this is reason why e x is one of my favourite functions :)
This is a very easy sum .
Log in to reply
I know. That's why it is rated a Level 1 in Calculus.
Log in to reply
Oh... Your Name looks like you are a Bangali... I am a bangali too.
Log in to reply
@Md Zuhair – Ah yeah I'm a bengali.
Log in to reply
@Arkajyoti Banerjee – Ar ei onko ta SN De 'r onko na?? If you know it :P
Log in to reply
@Md Zuhair – See the last line of the solution. It is not from Sourendranath De's book ;)
Problem Loading...
Note Loading...
Set Loading...
Looking forward to differentiate y ,
Therefore, its derivative is equal to the original function itself.
Question source: Derivatives - Example 2 - Mathematics For Class XI, R. D. Sharma (Pg 30.30)