A Self-Describing Number

The sum of the numbers is 7. When 3 + 2 + 1 + 1 + 0 + 0 + 0 = 7 It is the only possible ans.

Now there cant be 6 x 0 Because then there would be 1 x 6 and 2 x 1 and 1 x 2. Even so there cant be 5 x 0 Because then there would be 1 x 5 and 2 x 1 and 1 x 2. Even so there cant be 4 x 0 Because then there would be 1 x 4 and 2 x 1 and 1 x 2, but then we only have 3 x 0. Once again, the sum must be 7! And we have only 7 places to be filled. So there must me 3 x 0 and 1 x 3. When there is 1 x 3, there must be at least 1 x 1, so it is 2 x 1 and 1 x 2. Of course there is 0 x 4, 0 x 5 and 0 x 6.

The only seven digit number is 3211000. Therefore, that has to be the answer.

Sidenote to the maker of the question: A bit obvious ah....

3 on his head =3 and 2 big legs = 2 and 2 small legs = 11 and three zeros of white, yellow and pink colors.

the first digit is 3 and no.of zeros are also three second digit is 2 and no of one are also 2. two options contain only 6 digits so no way to chose it

The only answer with 7 digits :) 3211000

The only possible answer is 3211000 as it is only 7-digit number available and it meets the given requirements.

In the figure, there are 3 ears at the very top on the head of the dragon, it has 2 pairs of legs, but only 1 eye and 1 mouth respectively. Also, since it has no three (0), four(0) or five(0) similar/pair of body parts in the dragon. Hence it describes the 7-digit number 3211000

3 ceros, dos unos, un tres, un dos, cero cuatros, cincos y seis

no of zeros 3 so 1st digit noof 1s =2 sosecond digitthen no 3211000

Just find a answer that shown SEVEN digit (^.^)

3 on head, 2 hands, 1 pair of leg and no other number

I can see why this is a level 1. All that was needed to do was compare the answer choices to the description. Two out of four of the choices, weren't even a possibility after the first describing sentence.

There was only one 7-digit number (3211000) so you test it and it is right.

3 zeros,2 ones,1 threes,1 twos,0 fours ,0 fives,0 sixes

• Let the number we need to find to be F = abcdefg ( 0<=b,c,d,e,f,g<=6; 1<=a<=6)
• if e >=1, we need to fill 1 of 5 at least in other place and the number 4 must exist in F. Then, we need to fill 5 of numbers (h belongs to {0,1,2,3,4,6}) and fill 4 of numbers (t belongs to {0,1,2,3,4,6}{h}) => the number of digits we need to fill 1+1+5+4 =11 at least. (Eliminated)

• => e=0;

• f,g is similar to e. (f=g=0)

• => F = abcd000 => ( 0<= b,c,d<=3; 1<=a<=3)
• F has 3 of 0s at least => a>=3 => a= 3;
• F = 3bcd000 (0<=b,c<=3, 1<= d<=3)
• if d=2 => b =3 or c=3 and we don't have enough of the number of places to fill.
• => d=1.
• F= 3bc1000 (0<=c<=2, 1<=b<=2 coz we exactly have one of three, and at least one of one)
• if b=1, we have 2 of 1s but b=1 (eliminated)
• => b =2;
• F= 32c1000 => F=321000.

3211000 is the answer

3 zeros, 2 ones, 1 two, 1 three, 4 zeros, 5 zeros, 6 zeros

It is easy the question says that the first digit is the number of zeros so in 3211000 the first digit is 3 and there are also 3 zeros and the 2nd digit is 2 which shows the number of 1 and there are 2 one

easy one

a seven digit no. will be total sum of 7

Their are 3 0's, 2 1's, one 2 and one 3 and then no other numbers so therefore 0

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4100100

3211000

3211000

3 number of 0's, 2 number of 1's, 1 number of 2, 1 number of 3, 0 number of 4, 0 number of 5 and 0 number of 6

3 zeros, 2 ones, 1 two and 1 three.

3211000

first of all its the only one with seven digits and secondly the description is very explanatory.

Three 0's, two 1's, one 2, one 3

One answer is only 6 numbers, none isn't right (duh), and the one with the 7 isn't right because you would have to have 6 other 7's. PROCESS OF ELIMINATION!!!

As the question is said.......the only option matching is option c...

3211000

I simply count if how many digit are there in each choices. There is only one answer that has 7 digit (3211000) and that was my choice because the Question itself is asking for seven digit number.

as per the problem, the 3211000 contains three zeros,so the first digit must be 3 like that, it contains two 1's, so the second digit must be 2. other options not follow this condition.

in the number 321100, there are 3 zeros, 2 one, 1 twos, 1 threes, 0 fours and 0 fives

3211000 Because 3 zeros, 2 one , 1 two, 1 three, 0 four, 0 five

There was only one choice with 7 digits

3211000

in the number 3211000, there are 3 zeroes, 2 one, 1 two,