1+1 is not just 2 ...
What is 1 + 1 ?
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6 solutions
Discussions for this problem are now closed
That gave me tears, i bashed by trying the other possible options instead of this =.=|||
how would you do 1C2?
The convention is that it's taken as 0 ; ( k n ) = 0 for all k > n ≥ 0 .
Thank you!
why is that trignometric option wrong it gives cosec2(theta)-cot2(theta)=1
Yes, it gives 1 . And what is 1 + 1 ?
just verify all the options given there!! btw nice question @Aditya Raut !!
# NoBash fails, so # AlwaysBash
Wolfram alpha that ish!
This can't be a solution, please edit it and show how the options were verified by you. Thanks for that compliment , but make it a solution, or if you want to comment, wait for a solution to be posted.
I want to see the face of ppl when they see the problem and not the options. If I were to say to others, "A level 4 prob on Brilliant.org asks what is 1+1", they'd probably..... I don't know.. Nice thinking @Aditya Raut
Lol. I told my friend that and he was like WOW! WHERE IS IT!
(0.o) <--- my face
@Trevor Arashiro – ( -_- ) <--- mine
@Satvik Golechha – x_x calcing mode ON
now i dont have the options so that i can give solutions for them!! :P
Yes you have ! You can edit the solutions. If you are not getting how to do that, then post your views as a comment and I can add them to your solution as a moderator...
The one that is the answer has a small mistake. nCr has n>=r. The value of n in the question begins from n=1, which causes it to be 1C2, which violates it's domain
uh no 1C2=0 by definition
Option 1 is cocrect
Guys, as we all know that
∑nC2 where the limits of n is from 1 to k = (n+1)C3
Here n = 1 and k = 3 So, ∑nC2 from n = 1 to n = 100 is equal to 101C3 = 166650
∑nC2/ 83325 = 2
Based on following verifications, i found the answer.
1 . Regarding 1st, option (That appeared when i solved it), let us see an example, 5 − 2 ⌊ 2 5 ⌋ = 1 as the number gets higher,so is the separation.
5 9 − 1 0 ⌊ 1 0 5 9 ⌋ = 9 ,so its not 1st option
2 . I integrated, and noticed that there were terms ( 9 . 0 1 4 ) − 9 4 ) / 4 − 3 8 ( 9 . 0 1 3 − 9 3 ) and so on... you will notice since 9 . 0 1 4 = 6 5 9 0 . 2 0 8 6 3 6 0 1 and 9 . 0 1 3 = 7 5 1 . 4 3 2 7 0 1 thus we conclude there is no number to cancel the terms in decimal place.
4 . The trigonometry one was easiest giving the answer 1. So the answer is 3rd, the binomial coefficient one.
i used latex, inspite of that it came like this. if you are too eager to know remove the first two and last two characters and copy paste into any latex editor. sorry, tried my best.
Thanks. I corrected the error. You don't have to leave any spaces between the brackets. BTW Why did you use all that \quad in front of every word? You don't need to latex text...
Absolutely Satvik, why didn't YOU edit it to make it right? It's our duty as moderators !
@Aditya Raut – @Aditya Raut I edited the Latex so that it worked alright. But I didn't remove all that "\quad" because I wanted to know why they had taken so much pain to write it before every word. Thanks.
@Satvik Golechha – The main reason he had put \quad before every word is that I believe he didn't typed out the latex himself, I think he must be using a latex software like daum equation editor, initially I also write all the text into the daum equation editor and just copy paste it into my solutions and questions, that resulted in the word \quad behind every word.
@Ronak Agarwal – But why one needs that, we can simply wrap the math terms in LaTeX ! Not many people know that, and as moderators it's our duty to spread the knowledge of LaTeX too.... ^_^
I have edited your solution, please have a look at it from the pencil icon that appears (editing option), and try to understand what you have to wrap in your \ ( ..... \ ) formatting. ONLY the math terms , not whole text. Hope you understand it.
oh !!thank you very much guys. thats a relief!!
But there is one wrong thing in your solution, see that in the integral I've asked the f l o o r function on that integral, so even if those decimals don't get cancelled, that will give an integer answer, because integral is wrapped in ⌊ a ⌋ which means greatest integer ≤ a . @Vishwesh Ramanathan
I guess that you should have mentioned that [ ] was the Greatest Integer function. Got confused for a moment.
At first i got frightened "what the hell it is?" but then found the trick .Enjoyed bashing it.
Since it is well-known that k = 2 ∑ n ( 2 k ) = ( 3 n + 1 ) , substituting gives k = 2 ∑ 1 0 0 ( 2 k ) = ( 3 1 0 1 ) = 1 6 6 6 5 0 = 8 3 3 2 5 ⋅ ( 1 + 1 ) . Thus the answer is 8 3 3 2 5 n = 1 ∑ 1 0 0 ( 2 n ) .