Not many solutions? Part 2

Algebra Level 3

Let the functions f ( x ) f(x) and g ( x ) g(x) be f ( x ) = x 3 2 x 2 + x 2 f(x)=x^{3}-2x^{2}+x-2 and g ( x ) = x 2 + 1 g(x)=x^{2}+1 .

Find the sum of all real solutions to the equation

f ( x ) + g ( x ) = 0 f(x)+g(x)=0 .


Part 1 .


The answer is 1.

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1 solution

Tarmo Taipale
Jun 18, 2016

f ( x ) + g ( x ) = ( x 3 2 x 2 + x 2 ) + ( x 2 + 1 ) f(x)+g(x)=(x^{3}-2x^{2}+x-2)+(x^{2}+1) .

We get the equation

x 3 2 x 2 + x 2 + x 2 + 1 = 0 x^{3}-2x^{2}+x-2+x^{2}+1=0

x 3 x 2 + x 1 = 0 x^{3}-x^{2}+x-1=0

( x 1 ) ( x 2 + 1 ) = 0 (x-1)(x^{2}+1)=0

x = 1 x=1 or x 2 + 1 = 0 x^{2}+1=0 . The second equation of these two has no real solutions, so we get

x = 1 x=1 .

The only solution is 1, so the sum of all real solutions is also 1 \boxed{1} .

i and minus i works as well but their sum is 0 anyway

דניאל נוקראי - 4 years, 12 months ago

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Well, I simply thought complex numbers don't count, except if it is said otherwise. But now I have edited the question to ask for real numbers.

Tarmo Taipale - 4 years, 12 months ago

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Well then, the solutions should also be edited. Add "real" in front of "solutions"

Hung Woei Neoh - 4 years, 12 months ago

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@Hung Woei Neoh Of course.

Tarmo Taipale - 4 years, 12 months ago

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