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f ( x ) + g ( x ) = ( x 3 − 2 x 2 + x − 2 ) + ( x 2 + 1 ) .
We get the equation
x 3 − 2 x 2 + x − 2 + x 2 + 1 = 0
x 3 − x 2 + x − 1 = 0
( x − 1 ) ( x 2 + 1 ) = 0
x = 1 or x 2 + 1 = 0 . The second equation of these two has no real solutions, so we get
x = 1 .
The only solution is 1, so the sum of all real solutions is also 1 .