In a party 2015 people get together and shake hands with every person except the ones sitting adjacent to them supposing them to sit in a circle. Each person shakes hand with each other but only once.How many handshakes took place?
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Thanks Bro
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How did you think of such a solution? It's commendable! awesome
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It's Just like yours, only a bit quicker. U also did n(n-3)/2 didn't you. Your solution is also very nice .
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@Kushagra Sahni – C'mon modesty has a height! My solution is a common one .I just went with the rhythm of the question ,you thought out of the box. That's brilliance!
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@Raven Herd – Thanks Mate. Where are u from by the way, which state?
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@Kushagra Sahni – I think you must open your grade 3 SST book .They teach there that Lucknow is in Uttar Pradesh...
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@Raven Herd – I never opened your profile. I just saw you in the comments so only India was written that's why I asked.
Hey....this problem is similar to a problem which came in N M T C 2 0 1 4 paper.
Consider a person A among these 2015 people sitting in a circle .A cannot shake hands with her neighbours and ofcourse with herself so in a total 1 person shakes hand with 2015-3 =2012 people ,so A has to do 2012 handshakes and there are 2015 people in total so total number of handshakes =2012 2015 but consider another person B who will shake hands with A 2 times ;once done by A and another time by himself so we have counted 2 times .Thus the total number of handshakes is 2012 2015/2=2027090
Nice method :)
come on Kushagra bhaiyya, ma'am told us the solution !!
He told me the way just after the quiz and it was his thinking.
Bhai quiz dene k baad maam k paas kab gaya main? Mera answer sahi tha to maam k paas kyu jaaunga main?
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A great solution by my friend @Kushagra Sahni . Consider the problem as a polygon with 2015 corners. Now what is a diagonal? Line joining 2 corners except the adjacent ones. So just applying n(n-3)/2 you will get the answer