Obscure polynomial

Algebra Level 5

Let f ( x ) = x 4 3 a x 3 + b x 2 2 b x + 8 f(x) = x^4-3ax^3+bx^2-2bx+8

If one of the roots of this polynomial is 2 2 , find the sum of its other roots.


The answer is 1.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Discussions for this problem are now closed

Since f ( 2 ) = 0 f(2) = 0 , we have that f ( 2 ) = 16 24 a + 4 b 4 b + 8 = 0 a = 1 f(2) = 16 - 24a+ 4b - 4b + 8 = 0 \leftrightarrow a = 1 .

By Vieta's Formulae, the sum of the roots of the polynomial is 3 3 . Since one of them is 2 2 , the sum of its other roots is 1. \boxed{1.}


This can also be done by Briot-Ruffini's Algorithm and Girard's Relations.

Did in the same way

Sudhir Aripirala - 6 years, 4 months ago

Simple nice solution. Thanks.

Niranjan Khanderia - 6 years, 4 months ago
Jaikirat Sandhu
Jan 25, 2015

Since f(2) = 0, we have a = 1, Now, Sum of roots = 3a/1 = 3. One root is 2, therefore sum of others is 1.

This problem is really overrated!!

Shreya R - 6 years, 4 months ago

Yeah, sometimes it's hard to determine how hard your own problems are. I created this one because I've never seen a problem like this, in which one of the coefficients cancels out. And it's actually "obscure" at first glance (you see two variables and little info), but since the only info given is that one of the roots is 2 2 , everyone that sees the problem tries to use it. lol

Rick B - 6 years, 4 months ago

I like this problem. Thanks for creating it.

Soumo Mukherjee - 6 years, 4 months ago

@Soumo Mukherjee Thanks. :D

Rick B - 6 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...