Optics.. #2

Classical Mechanics Level 4

The above figure shows an irregular material of refractive index $\sqrt{2}$ . A ray of light strikes the surface AB as shown in the figure. After refraction it is incident on a spherical surface CD of radius of curvature 0.4 m and enters medium of refractive index 1.514 to meet PQ at E . Find the distance OE .

Find the answer upto two decimal places .

All measurement are in meters .

Refractive index on the right side of the glass slab is 1.514 .

The ray initially is in vacuum .

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The answer is 6.06.

1 solution

Harshvardhan Mehta
Feb 14, 2015

Please edit your question and state clearly what we have to find.

Purushottam Abhisheikh - 6 years, 3 months ago

yep done and thanks for pointing out the mistake. :)

Harshvardhan Mehta - 6 years, 3 months ago

@Harshvardhan Mehta is it an old IIT JEE problem? ?

siddharth bhatt - 6 years, 3 months ago

@Siddharth Bhatt – yep it is.. but a quite old one.

Harshvardhan Mehta - 6 years, 3 months ago

It does not appear to me that you stated what we have to find.

Calvin Lin Staff - 6 years, 3 months ago

@Calvin Lin – Sir , I had corrected the problem and added what is needed to fiind two times but somehow i dont know it dint appear. is it alright now?

Harshvardhan Mehta - 6 years, 3 months ago

@Harshvardhan Mehta – Thanks. The only changes that I see you making prior to my report / first comment, as adding, then editing, then removing "This not my original. t is an old IIT question."

Calvin Lin Staff - 6 years, 3 months ago

@Calvin Lin – ohk maybe it dint get updated due to some net problems... thanks once again for bringing to my notice. by the way can you please start the level grading system for chemistry and are there brilliant shirts available in exchange of points as it used to be before.. i had also asked about this in your message board but dint get any reply.. so please respond

Harshvardhan Mehta - 6 years, 3 months ago

@Harshvardhan Mehta – @Harshvardhan Mehta , can you also specify that initially it is refractive index 1? i.e. On the left side of the slab, it is vacuum? I took it to be the same material as the right side of the slab because no information was given, and so could not solve the question....

Kp Govind - 6 years, 3 months ago

@Kp Govind – well I guess I have mentioned in the figure the value of refractive index as 1.154 ...

Harshvardhan Mehta - 6 years, 3 months ago

@Harshvardhan Mehta – That is on the right side of the slab. Initially when the light ray is travelling from the left, you have not specified the refractive index of the medium it is from.

The common man might assume it to be the same material as on the right side of the slab, but it isn't. It is actually just vacuum.

Kp Govind - 6 years, 3 months ago

@Kp Govind – ohk i'll mention it thanks for bringing to my notice..

Harshvardhan Mehta - 6 years, 3 months ago

Thanks! In future, if you spot any errors with a problem, you can “report” it by selecting the “dot dot dot” menu in the lower right corner.

Calvin Lin Staff - 6 years, 3 months ago

@Harshvardhan Mehta While using snell's law, you have used the refractive index of the medium before the surface AB as 1 which means that the medium is vacuum. But in the diagram you have given that refractive index is 1.514 outside the glass slab. So, according to your solution, you must shade the region to the right of surface CD and you must mention that it is vacuum to the left of surface AB. Please correct me if you meant to say something else..

Vighnesh Raut - 6 years, 1 month ago

@Vighnesh Raut – Well we have always been taught and told when refractive index of any medium is not given then we have to consider it to be vacuum. But i think I better mention it . thanks . $\ddot \smile$

Harshvardhan Mehta - 6 years, 1 month ago

Optics.. #2

To try more such problems click here .

The answer is 6.06.

1 solution

1 pending report

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