Oxidation number 2

Chemistry Level 2

Find the sum of the oxidation numbers of Zn, Si and Ba in the following ion and molecules: $\text{Zn(OH)}^{-2}_{4}, \text{SiH}_{4}, \text{BaH}_{2}.$

0

2

4

-4

2 solutions

Avi Aryan
Jun 8, 2014

ON of Zn = $+2$
ON of Si = $-4$
ON of Ba = $+2$ because Ba is less electro-negative than H. See a table here.

Baidehi Chattopadhyay
May 11, 2014

Oxidation number of Zn is 6, that of Si is -4 and that of Ba is -2. So sum= 6-6=0

I thought Zn is 2. O.N. of OH=-1 isn't it? so

$x - 4 = -2$

$x = oxidation number of Zn$

Pinak Wadikar - 7 years ago

Exactly , even I thought the same @Pinak Wadikar

Krishna Ar - 7 years ago

@Krishna Ar do you think the problem is correct?

Pinak Wadikar - 7 years ago

@Pinak Wadikar – I don't think so. I think it is totally wrong. Shall we report this problem?

Krishna Ar - 7 years ago

@Krishna Ar – See my answer

Avi Aryan - 7 years ago

@Pinak Wadikar – Or does the oxidation number vary for Oh-?

Krishna Ar - 7 years ago