Parallel resistors

Since the resistors are parallel. We get 1/6+1/12+1/18=11/36. 36/11=3.27ohms/weird horseshoes.

Hello,

for parallel circuit, as given those resistors,let R1= 12 ohms , R2 = 18 ohms, R3= 6 ohms...

Rtot(R1,R2) = R1R2 / (R1+R2) = (12)(18) / (12+18) = 7.2 ohms,

Rtotal(R1,R2,R3) = 7.2(R3) / (R3 + 7.2) = 7.2(6) / (7.2 + 6) = 3.273 ohms....

Thanks....

they are connected in parallel R=[(R1^-1)+(R2^-1)+(R3^-1)]^-1 R=[(12^-1)+(18^-1)+(6^-1)]^-1 R=3.27 ohms

Since it is parallel, so..

$\frac{1}{R_{total}}=\frac{1}{12}+\frac{1}{18}+\frac{1}{6}$

$\frac{1}{R_{total}}=\frac{3+2+6}{36}$

$\frac{1}{R_{total}}=\frac{11}{36}$

Then..

$R_{total}=\frac{36}{11}$

$R_{total}=3.272$

Since resistor was connecting in parallel ckt. formula to be use is 1/TotR=1/r1+1/r2+1/r3 1/TotR = 1/6+1/12+1/18 TotR =1/ 0.17r+0.08r+0.05r TotR =1/0.3r =3.33r

Rt1=R1(R2)/R1+R2

Rt=R3(Rt1)/R3+Rt1

first get the initial resistance with last two parallel resistor then lastly same formula to derive with 3.27 ohms

formula for finding combined resistance in parallel circuit is: 1/R= (1/a)+(1/b)+(1/c).... It depends how many resistors are there in the circuit

(1/(1/12 +1/18 +1/6)) = 3.27 ohms

1/Rtot=1/R1 plus 1/R2 Plus 1/R3 since they are parallel. =1/6+1/12+1/18 =11/36 Get the reciprocal 36/11 or 3.27.

these are connect in parell

Formula for parallel resistance in a circuit is 1 ---------------------------------- 1/R1 +1/R2 +1/R3 Substituting the values in above,we get 36/11 = 3.3 Ans K.K.GARG.India