Square Factorials

Which of the following is a perfect square ?

Notation : ! ! denotes the factorial notation. For example, 8 ! = 1 × 2 × 3 × × 8 8! = 1\times2\times3\times\cdots\times8 .

97 ! × 98 ! 97!\times98! 98 ! × 99 ! 98!\times99! 99 ! × 100 ! 99!\times100! 100 ! × 101 ! 100!\times101!

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3 solutions

展豪 張
Jun 1, 2016

Relevant wiki: Perfect Squares, Cubes, and Powers

n ! × ( n + 1 ) ! = ( n + 1 ) ( n ! ) 2 n!\times(n+1)!=(n+1)(n!)^2 is a perfect square iff n + 1 n+1 is a perfect square.
The only option is 99 ! × 100 ! 99!\times 100! where 100 100 itself is a perfect square.

That is absolutely correct.

Hana Wehbi - 5 years ago

This problem is already posted by me, @Hana Nakkache , here .

Anish Harsha - 5 years ago

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I am sorry, I saw similar problem in one of my kids homework so I thought it would be nice to post it. If you want me to delete it, let me know.

Hana Wehbi - 5 years ago

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No No . No need to delete. Let it be, it's a good problem.

Anish Harsha - 5 years ago

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@Anish Harsha Thank you so much.

Hana Wehbi - 5 years ago
Ashish Menon
Jun 5, 2016

99 ! × 100 ! = 99 ! × 99 ! × 100 = ( 99 ! ) 2 × 10 2 = ( 10 × 99 ! ) 2 99! × 100! = 99! × 99! × 100 = {\left(99!\right)}^{2} × {10}^2 = {\left(10 × 99!\right)}^2 .
So, 99 ! × 100 ! \color{#3D99F6}{\boxed{99! × 100!}} is a perfect square.

Absolutely correct.

Hana Wehbi - 5 years ago
Aniruddha Bagchi
Jun 11, 2016

It's 99! x 100!. Because we can rewrite it as 99! x 99! x 100 and that's a perfect square . Nice question , Hana. One must know to play with factorials to solve this question.

Thank you.

Hana Wehbi - 5 years ago

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