Pet Show!
At the Pet Show which showcases dogs, cats, and fish, I noticed that:
- all except two of the entries were cats,
- all except two were dogs,
- and all except two were fish.
What are the total number of animals were at the Pet Show?(dog, cat, fish)
This is a part of the set: Logic
Try this: All of my problems
The answer is 3.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
3 solutions
But, since the question is: "How many of EACH animal were at the Pet Show", shouldn't the answer be 1?
Log in to reply
You are right sir, i also tried entering 1 but then I thought he might be saying about total number of animals. His questions generally are stated very poorly
Log in to reply
Yeah, i entered 1 aswell and i was confused to see it's false. So, i just saw the solution and i was even more confused :P Thanks for clarifying!
1 + 1 + 1 = 3 animals. However, 'I have edited the question to What are the total number animals were at the pet show?'.
1 + 1 + 1 = 3 animals. However, 'I have edited the question to What are the total number animals were at the pet show?'.
let the number of dogs be d, cats be c and fish be f.
The equations we get from the statements are: (d+c+f)-d=2, (d+c+f)-c=2 and (d+c+f)-f=2. Simplfying, d+c=2, d+f=2 and d+c=2.
Adding the 3 equations together, we get: 2d+2c+2f=6, d+c+f=3
Let N d o g s be the number of dogs, N c a t s the number of cats, and N f i s h the number of fish.
There are two not-dogs ⟹ N c a t s + N f i s h = 2
There are two not-cats ⟹ N d o g s + N f i s h = 2
There are two not-fish ⟹ N c a t s + N d o g s = 2
Solution: N c a t s = N d o g s = N f i s h = 1
Total: 1 + 1 + 1 = 3
What is N ?
Log in to reply
Number, number of cats, number of fish, etc. Sorry about that.
Log in to reply
Then you should add a side note that N means number.
Log in to reply
@Munem Shahriar – Done, and in more than just a side note. Thanks.
We could have 2 pets: 1 turtle, 1 snake.
It satisfies the conditions of the problem.
You missed the term " N n o n e ".
Log in to reply
I thought about that, and was going to introduce two crocodiles, but then I re-read the statement of the problem and took the list in parentheses at the end, "(dog, cat, fish)," to mean that only dogs, cats, and fishes were allowed into the show. I felt that the condition should have been included higher up in the statement, but was still satisfactory where it was.
Log in to reply
Right, I have issues with the phrasing of the question.
I've reported this, and will let @Munem Sahariar deal with it.
All except two were dogs and all except two were cats. So two animals were not dogs and two animals were not cats. One of the "not dogs" could have been a cat, and one of the "not the cats" could have been a dog. Combine this with the fact that all except two of the pets were fish and we have the result:
One dog, one cat, one fish.
Therefore (1+1+1 = 3) animals were at the Pet Show