Phi with a and b

Algebra Level 4

The square root of phi can be expressed as the sixth root of the quantity root a plus b. What is a minus b?

In other words, ϕ = a + b 6 \sqrt{\phi}=\sqrt[6]{\sqrt{a}+b}


The answer is 3.

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3 solutions

Daniel Liu
Apr 26, 2014

We have φ 3 = 5 + 2 \varphi^3=\sqrt{5}+2 so the answer is 5 2 = 3 5-2=\boxed{3} .

Exactly bro. :D

Finn Hulse - 7 years, 1 month ago

Nice solution, I thought it was much more difficult so i rated it level 4. Oops.

Nathan Ramesh - 7 years, 1 month ago

Why is ϕ 3 = 5 + 2 \phi^{3} = \sqrt5 + 2 ?

Omkar Kulkarni - 6 years, 5 months ago

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phi is defined as 5 + 1 2 \sqrt{5}+\frac{1}{2} Cubing this results in 5 + 2 \sqrt{5}+2

Lawrence Mayne - 6 years, 2 months ago

ϕ = 1 + 5 2 \phi=\dfrac{1+\sqrt5}{2} , which is the positive root of x 2 x 1 = 0 x^2-x-1=0 . But x 2 x 1 = 0 x 2 = x + 1 x 3 = x 2 + x = 2 x + 1 x^2-x-1=0~\Rightarrow~x^2=x+1~\Rightarrow~x^3=x^2+x=2x+1 .

So ϕ 3 = 2 ϕ + 1 = 2 + 5 \phi^3=2\phi+1=2+\sqrt5 .

Laurent Shorts - 4 years, 3 months ago

ϕ = a + b 6 \sqrt{\phi}=\sqrt[6]{\sqrt{a}+b} ( ϕ ) 3 = a + b (\phi)^3=\sqrt{a}+b 5 + 2 = a + b \sqrt{5}+2=\sqrt{a}+b So a = 5 , b = 2 a=5,b=2 and a b = 5 2 = 3 a-b=5-2=\boxed{3}

Finn Hulse
Apr 26, 2014

Nice problem Nathan. :D

:D people are telling me it's pronounced fie and not fee like I thought it was so it doesn't rhyme :(

Nathan Ramesh - 7 years, 1 month ago

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Both pronunciations are correct I think.

Daniel Liu - 7 years, 1 month ago

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I think it's pronounced "phi" with an "iy" sound. Rhymes with pi. Actually, I went to a Latin camp and that's what it is. I memorized the whole Greek alphabet. Daniel, what language are you taking?

Finn Hulse - 7 years, 1 month ago

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@Finn Hulse Japanese 1st year. Fluent in English and Chinese (kinda :P)

Daniel Liu - 7 years, 1 month ago

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@Daniel Liu Dang you're lucky to go to such a good school. My school is one of the worst in the country but my French teacher is unbeivably good.

Finn Hulse - 7 years, 1 month ago

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