Pokémon elimination grid 1

Logic Level 4

The image above ( detailed view here ) shows how a Pokemon's type can affect the damage it takes from an attack.

We are given certain information about five Pokemon A , B , C , D , E A,B,C,D,E .

  1. All five Pokemon are of a distinct type and also have that type of attack.

  2. Pokemon A's attack do not do × 2 \times 2 damage to any type.

  3. Pokemon B only takes × 1 \times 1 damage from Pokemon A , C , D , A, C, D, and E . E.

  4. Pokemon C's attacks do × 2 \times 2 damage to three of the other given Pokemon ( A , B , D , E A,B,D,E ). It also takes × . 5 \times .5 damage from only two of the other given Pokemon.

  5. Pokemon E's attack does × 1 \times 1 to its own type.

What is the typing of Pokemon D?

Details and Assumptions

From the chart, the attack's power is multiplied by the given power against certain types. i.e fighting types are multiplied × 2 \times 2 against steel types.

Rock Steel Dragon Ice Normal Dark

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1 solution

Tran Hieu
Jan 11, 2016

Note: The detail about STAB is very confusing and should be remove. It contributes nothing to the solution and instead make me wonder where do I get the type of the move.

  • From 1. we could see A is the Normal type: Only row have no green cell.

  • From 3 we could see C is the Fight type, only that type could do x2 damage to Normal type (A).

  • From 3 and 5, we could see E is the Rock type, as only the Rock type do x1 to itself and take x2 from Fight type.

  • From 2 and the above we can see that B could only be of the type: Water,Grass,Electric,Dragon, as only those type take x1 damage from Normal, Fight and Rock. But none of those type deal x0.5 damage to Fight type (C), and A deals x1 damage to C, so from 3 we see that D deals x0.5 damage to C.

  • From that, and C deal x2 damage to D, we could conclude that D is Dark \boxed{\text{Dark}} (because E is already Rock)

This is exactly how i intended for someone to solve the problem(+1). I have edited the problem by removing STAB.

Aareyan Manzoor - 5 years, 5 months ago

From 3 we could see C is the Fight type, only that type could do x2 damage to Normal type (A).

Why does C have to do 2x damage to A? C only has to do 2x damage to three of the Pokemon. These might not include A.

Ivan Koswara - 5 years, 5 months ago

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I had rewritten the c to do 2x damage to (a,b,d,e) but you might not have seen that!

going down this road we can have C ghost or dragon instead of fight! But ghost types are super effective only against two (ghost and psychic) and dragon 1( dragon). so that was not possible !

Aareyan Manzoor - 5 years, 5 months ago

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Oh, I might have missed that when I edited. You can edit your problem again and verify/edit the facts so that they are as you intend.

Ivan Koswara - 5 years, 5 months ago

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@Ivan Koswara Dont worry! i have edited a fact to make this easier.adding C to the list kept the answer the same but more workout was required.

Aareyan Manzoor - 5 years, 5 months ago

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@Aareyan Manzoor The problem is still unanswered then; if C only deals 2x damage to three of A,B,D,E, why can you (or the solution writer, in this case) conclude that C deals 2x damage to A?

Ivan Koswara - 5 years, 5 months ago

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@Ivan Koswara We are given B takes 1x damage from all(except itself). So C cannot do 2x damage to it and the only ones left are A,D,E to take 2x damage from C.

Aareyan Manzoor - 5 years, 5 months ago

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@Aareyan Manzoor ...oh, okay. Yes, that makes the solution logical.

Ivan Koswara - 5 years, 5 months ago

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