Polygon
Geometry
Level
2
A polygon has 27 diagonals.The number of sides of the polygon is:
The answer is 9.
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1 solution
Peace be upon you,
By using this formula,
number of distinct diagonals = [ n(n-3) ] / 2 ,
as n = number of sides ,
27(2) = n^2 - 3n,
n^2 - 3n - 54 = 0,
(n -9 ) ( n + 6 ) = 0,
take + value , ignore - , as per logic...
thanks...