Polynomial 2.2

Algebra Level 2

x 3 + 2 x 2 x = 2 \large x^{3} + 2x^{2} - x = 2

What is the sum of all the solutions to the equation above?


The answer is -2.

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3 solutions

Brandon Stocks
May 7, 2016

x 3 + 2 x 2 x 2 = 0 x^{3} + 2x^{2} - x - 2 = 0

x 2 ( x + 2 ) ( x + 2 ) = 0 x^{2}(x+2) - (x+2) = 0

( x + 2 ) [ x 2 1 ] = 0 (x+2)[ x^{2} - 1 ] =0

( x + 2 ) ( x 1 ) ( x + 1 ) = 0 (x+2)(x-1)(x+1) = 0

From the last equation you can see three equations

x + 2 = 0 , x = 2 x+2 = 0 \; , \; x = -2

x 1 = 0 , x = 1 x-1 = 0 \; , \; x = 1

x + 1 = 0 , x = 1 x+1 = 0 \; , \; x = -1

The sum of the three solutions is (-2) + 1 + (-1) = -2

Using Vieta's formula.

x 3 + 2 x 2 x 2 = 0 \Rightarrow x^3+2x^2-x-2=0

Sum of roots = b a = 2 \text{Sum of roots}=\dfrac{-b}{a}=\boxed{-2}

Abhay where does this come from?

Brandon Stocks - 5 years, 1 month ago

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Vieta's formula, click the link in his solution to learn more

Hung Woei Neoh - 5 years, 1 month ago

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If I understood it the equation -b/a applies to second degree equations? This is a third degree equation.

Brandon Stocks - 5 years, 1 month ago

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@Brandon Stocks No, see it.

A Former Brilliant Member - 5 years, 1 month ago

Click Vieta's formula link and learn it.

A Former Brilliant Member - 5 years, 1 month ago

Ah, I totally forgot I could do this instead!

Hung Woei Neoh - 5 years, 1 month ago

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Lol...No problem. :)

A Former Brilliant Member - 5 years, 1 month ago
Hung Woei Neoh
May 7, 2016

x 3 + 2 x 2 x 2 = 0 x^3+2x^2-x-2=0

Notice that: 1 + 2 1 2 = 0 1+2-1-2=0

Therefore, x = 1 x=1 is a solution to the equation.

Rewrite:

x 3 x 2 + 3 x 2 3 x + 2 x 2 = 0 x 2 ( x 1 ) + 3 x ( x 1 ) + 2 ( x 1 ) = 0 ( x 1 ) ( x 2 + 3 x + 2 ) = 0 ( x 1 ) ( x + 2 ) ( x + 1 ) = 0 x = 2 , 1 , 1 x^3 - x^2 + 3x^2 -3x + 2x - 2 =0\\ x^2(x-1) + 3x(x-1) + 2(x-1) = 0\\ (x-1)(x^2+3x+2)=0\\ (x-1)(x+2)(x+1) = 0\\ x=-2,-1,1

The sum of all the solutions = 2 + ( 1 ) + 1 = 2 =-2+ (-1) + 1 = \boxed{-2}

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