Possible or Impossible?

Algebra Level 2

{ x + y + z 3 = 0 x y + z + 1 = 0 x + y z 1 = 0 x y z + 3 = 0 \begin{cases} x + y + z - 3 = 0 \\ x - y + z + 1 = 0 \\ x + y - z - 1 = 0\\ x - y - z +3 = 0\end{cases}

Is it possible for x , y , z x,y,z to satisfy the system of the equations above?

Bonus : If it is possible, give your answer as the sum of the values of x , y , z x, y, z .

Yes, it is possible No, it is not possible

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3 solutions

Mahdi Raza
Jun 20, 2020
  • ( 2 ) + ( 3 ) 2 x = 0 x = 0 (2) + (3) \implies 2x = 0 \implies \boxed{x=0}

  • ( 1 ) + ( 3 ) 2 x + 2 y = 4 y = 2 (1) + (3) \implies 2x + 2y = 4 \implies \boxed{y = 2}

  • Substitute in any equation z = 1 \implies \boxed{z = 1}

We see that it a solution is possible, thus the answer to be inputted is 1


Bonus answer: The sum is 3

@Mahdi Raza , did you read the question - you're supposed to give the answer as 1 1 or 0 0 .

Also, attempt the bonus...

A Former Brilliant Member - 11 months, 3 weeks ago

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The answer can only be 1 \boxed{1} or 3 \boxed{3}

Mahdi Raza - 11 months, 3 weeks ago

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You can't have both, so better remove the bonus part

Mahdi Raza - 11 months, 3 weeks ago

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@Mahdi Raza No, the bonus is if it's possible. I should've put - give your answer to the Bonus in the discussion...

@Mahdi Raza

A Former Brilliant Member - 11 months, 3 weeks ago

Solving the first three equations using Kramer's rule, we get x = 0 , y = 2 , z = 1 x=0,y=2,z=1 . Substituting in the fourth, we see that this equation is satisfied by these values of the unknowns.

@Alak Bhattacharya , can you show us how you used Cramer's rule to solve the first three equations?

A Former Brilliant Member - 11 months, 3 weeks ago

x = 0 , y = 1 , z = 2 x=0, y=1, z=2

Not to be rude @Páll Márton , but you need to show how you got the solution.

A Former Brilliant Member - 11 months, 3 weeks ago

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Same way as @Mahdi Raza

A Former Brilliant Member - 11 months, 3 weeks ago

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He got y = 2 , z = 1 y = 2, z = 1 ...

A Former Brilliant Member - 11 months, 3 weeks ago

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@A Former Brilliant Member Ok, I misspelled :)

A Former Brilliant Member - 11 months, 3 weeks ago

@A Former Brilliant Member That is because y y and z z are symmetric here

Mahdi Raza - 11 months, 3 weeks ago

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