Power of a resistor

Given the above diagram, what is the maximum possible power in watts that can be delivered to the 7 Ω 7\Omega resistor, if the resistor R R can be adjusted to any value?


The answer is 7.

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2 solutions

Chew-Seong Cheong
Apr 30, 2015

The voltage across resistor R R and 7 Ω 7\Omega resistor is (13-6=7V). The maximum current through the 7 Ω 7\Omega resistor is when R = 0 R=0 , then the current through the 7 Ω 7\Omega resistor is = 13 6 7 = 1 A =\dfrac {13-6}{7} = 1A and the maximum power delivered to the 7 Ω 7\Omega resistor = 1 2 × 7 = 7 W =1^2\times 7 = \boxed{7}W .

Ross Gunderson
May 1, 2015

I solved it a similar way as Chew-Seong, I used Kirchhoff's laws and set up a matrix. The thing is, I didn't fully understand what the question was asking and answered a different question in my tinkering. What I initially thought the question was asking was, What is the value of R R , such that the power dissipated by it is maximized? This should be a follow up question.

@Ross Gunderson , Well knowing that R = 0 R=0 in necessary to solve for the power.

Beakal Tiliksew - 6 years, 1 month ago

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If you want to maximize the power dissipated by that resistor, then the value of R cannot be zero. It's a different problem altogether.

Ross Gunderson - 6 years, 1 month ago

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If R is set to 0 than the total resistance on the path containing the 7 ohm resistor is 7 ohms. The voltage is the difference of the two cells, 7 Volts. Power can be obtained by (V^2)/R, giving you a power of 7W.

Liam Bury - 6 years, 1 month ago

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@Liam Bury Maximum Power is absorbed by the 7 ohm resistor when R = 70/3, under that condition the value of absorbed power by it is 0.1575 watts. In general, the power absorbed by the 7 ohm resistor for any value of R is = 7* {(70-6R)/(70-3R)}^2 . In anyways, Power absorbed depends on the value of R .

Ramji Singh - 6 years, 1 month ago

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