Predicting a Die Roll

Two independent, fair 6 sided dice are rolled. The first die face shows a 3 3 . The second die rolls under the table, so you can not see its face. The probability that the dice under the table is 3 3 given that the first dice is 3 3 can be written as a b \frac{a}{b} , where a a and b b are positive coprime integers. What is the value of a + b a + b ?


The answer is 7.

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4 solutions

Ewerton Cassiano
Nov 17, 2013
  1. How a die roll has 6 sides. Soon, this is the total of chances, and 3 is 1 1 possibility between 6 6 . Applying in the fraction, we can see:
    1. -> a b \frac{a}{b} ={ 1 6 \frac{1}{6} }.
    2. The sum of a a and b b is = 1 1 + 6 6 = 7 \boxed{7}

The question makes me confused. :/

Adam Zaim - 7 years, 6 months ago

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How?

Ewerton Cassiano - 7 years, 6 months ago

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If you are talking about the answer is simple, because the total of possibilities is 6 6 and 3 3 is 1 1 of 6 6 . Soon, we need to use in the formula : a b \frac {a}{b} , where b = 6 b = 6 and a = 1 a = 1 . 1 6 \frac{1}{6} = 1 + 6 1 + 6 = 7 \boxed{7}

Ewerton Cassiano - 7 years, 6 months ago

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@Ewerton Cassiano I already know that the probability stuff. It's the question. English is not my first language. So yeah. :/

Adam Zaim - 7 years, 6 months ago

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@Adam Zaim ok, I'm sorry

Ewerton Cassiano - 7 years, 6 months ago

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@Ewerton Cassiano If you start a new discussion about the language you will get information of this

Ewerton Cassiano - 7 years, 6 months ago

how can a die have the seventh side..?

Unfaithful Angel - 7 years, 6 months ago

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This isn't a seventh side, because it is only the sum of possibilities with the total , so 1 1 + 6 6 = 7 \boxed{7}

Ewerton Cassiano - 7 years, 6 months ago
Tom Engelsman
Aug 23, 2020

We have 36 ordered-pair combinations for our fair 2-dice sample space. Let A A be the event a 3 is rolled on the first die and B B be the event a 3 appears on the second die. This conditional probability is just:

P ( A B ) = P ( A B ) P ( A ) = 1 / 36 6 / 36 = 1 6 . P(A|B) = \frac{P(A \cap B)}{P(A)} = \frac{1/36}{6/36} = \boxed{\frac{1}{6}}.

Hence, a = 1 , b = 6 a + b = 7 . a = 1, b = 6 \Rightarrow a+b = \boxed{7}.

Himanshu Garg
Dec 19, 2013

First dice shows 3.

Now the possible combinations with other dice hidden are: (3,1) (3,2) (3,3) (3,4) (3,5) (3,6).

Total possibilities = 6.

Possibility we need, i.e. (3,3) = 1.

Probability = 1/6, i.e. a = 1 & b = 6.

did you ever know what a dice is or you do not understand the proble clearly?you know why?the solution is to know whats below the 3 and its 4 3+4=7ok?

Carl De Guzman - 7 years, 2 months ago

firt choice is 3 that is it is constant....so the probability of getting second dice 3 is 1-5/6....that is 1/6 so a+b=1+6=7....ans..

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