Prime Factor

( 2000 1000 ) \large \binom{2000}{1000}

Determine the largest 3 digit prime factor of the above number.


The answer is 661.

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2 solutions

Mark Hennings
Mar 29, 2018

If p p is prime and 1000 > p > 661 1000 > p > 661 , then 3 p > 2000 3p > 2000 and so the only multiples of p p between 1 1 and 2000 2000 are p p and 2 p 2p . Thus the index of p p in 2000 ! 2000! is 2 2 . In addition the index of p p in 1000 ! 1000! is 1 1 , and hence the index of p p in ( 2000 1000 ) \binom{2000}{1000} is 0 0 , meaning that p p is not a factor of ( 2000 1000 ) \binom{2000}{1000} . On the other hand 3 × 661 = 1983 < 2000 3 \times 661 = 1983< 2000 , and so the index of 661 661 in 2000 ! 2000! is 3 3 , while the index of 661 661 in 1000 ! 1000! is 1 1 . Thus the index of 661 661 in ( 2000 1000 ) \binom{2000}{1000} is 1 1 , and hence 661 \boxed{661} divides ( 2000 1000 ) \binom{2000}{1000} , and so is the largest 3 3 -digit prime factor of ( 2000 1000 ) \binom{2000}{1000} .

Sir, I think your answer is to the problem- Prove that 661 is the largest 3 digit prime factor of ( 2000 1000 ) \binom{2000}{1000}

How did you initially got the number 661?

Vilakshan Gupta - 3 years, 2 months ago

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No, since any prime number greater than 1000 1000 and less than 2000 2000 will divide ( 2000 1000 ) \binom{2000}{1000} .

Mark Hennings - 3 years, 2 months ago

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I am sorry, I wanted to say you have proved that 661 is the largest 3 digit prime factor of ( 2000 1000 ) \binom{2000}{1000} , but how did you get the number 661. Like you started from 1000>p>661...

(In the first comment, I missed "3 digit").

Vilakshan Gupta - 3 years, 2 months ago

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@Vilakshan Gupta By looking for indices, just as in my proof. Any 3 3 -digit prime greater than 500 500 has index 1 1 in 1000 ! 1000! , so we are just looking for such primes with index greater than 2 2 in 2000 ! 2000! . Since 661 661 is the largest prime less than 2000 3 \tfrac{2000}{3} , we are done.

Mark Hennings - 3 years, 2 months ago
Giorgos K.
Mar 27, 2018

Mathematica

Max@Select[First /@ FactorInteger@Binomial[2000,1000],#<1000&]

returns 661

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