The roots of the quadratic equation 3 x 2 − 2 k x + k + 4 = 0 are α and β . If α 2 + β 2 = 9 1 6 , find the sum of all possible values of k .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
done by the same method
Hey the equation is coming out to be: 12k^2 - 2k - 24=0. Whose solutions are -4/3 and 3/2. So the sum is 1/6 or 0.167. Where am I wrong??
Log in to reply
You are wrong with the equation you obtained. How did you obtain it?
Log in to reply
Is ABC formula wrong Vietas formula wrong?
-b(+/-)√(b^2-4a.c)/2.a
I got k 4 and 2.5 which is the sum gone to 6.5 .
Log in to reply
@Hafizh Ahsan Permana – bro, u must have got -2.5, check it!
The roots of the equation what u got are 8 and 9
same method!!!!
haha!!! guys we all have same approach towards this, i.e the veita function :)
using To-ong's little theorem
Can you please tell what is that theorem?
Problem Loading...
Note Loading...
Set Loading...
Rewrite the given expression:
( α + β ) 2 − 2 α β = 9 1 6
Now, by Vieta's formulas:
( 3 2 k ) 2 − 2 ( 3 k + 4 ) = 9 1 6
Rearrange and simplify:
4 k 2 − 6 k − 4 0 = 0
Again, by Vieta's formulas, the sum of all values of k is 2 3 = 1 . 5