Properties of matter!

Classical Mechanics Level 3

When a metal wire elongates by hanging a load on it, the gravitational potential energy is decreased.

This energy completely appears as heat. This energy completely appears as the increased elastic potential energy of the wire. None of these. This energy completely appears as the increased kinetic energy of the block.

View wiki
Keshav Tiwari by Keshav Tiwari , 23, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The energy is transferred into Heat and Elastic Potential energy. That means none of these have a 100% transformation only to them. Some is transferred to Heat which is literally the Heat Loss and maximum is transformed to elastic potential energy.

For interested mechanics geek, The wire with initial length, L L , cross section, A A , Young's modulus, Y Y and stretched with a length, l l has an Elastic Potential energy, E = 1 2 A Y L l 2 E=\frac{1}{2}\frac{AY}{L}l^2

Actually all of the options are correct but together, not individually!

5 Helpful 0 Interesting 0 Brilliant 0 Confused

Yes , that' s it . Good work . Upvoted ! : ) :)

Keshav Tiwari - 5 years, 6 months ago

Log in to reply

I was thinking that I should add the Integration method for the equation.

You can post a new solution if you feel so !

Muhammad Arifur Rahman - 5 years, 6 months ago

Log in to reply

Yes that's what i had in mind when i first saw the question . I'll post the method if someone wants me to . : ) :)

Keshav Tiwari - 5 years, 6 months ago

Log in to reply

@Keshav Tiwari – Pls upload integration method

Manojkumar Das - 3 years, 8 months ago

But there is a problem with this.. Okay, so you are telling half of the potential energy goes away as heat, as a result of the elongation?? Then when the load is removed it gains back its elastic potential energy, how is it possible to regain the lost energy? So then how would you explain this?? Decrease in Potential energy =mgl (l-elongation) Stored as elastic potential energy= 0.5 mgl (Area of the load- elongation curve) It does not appear as kinetic energy, because the rod is in equilibrium with the load in its new static position. **(I don't know what happens to the remaining, but this just got me thinking)

Alvin Cheriyan - 3 years, 7 months ago

Log in to reply

@Alvin cheriyan Why do think it can't regain its lost energy?

Keshav Tiwari - 3 years, 7 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...