In the above figure, P 1 and P 2 are massless pulleys, P 1 is fixed and P 2 can move. Masses A , B and C are 6 4 9 m , 2 m and m respectively. All surfaces are smooth and the string is massless. If it is given that θ = tan − 1 ( 4 3 ) , find the magnitude of acceleration of block C in ms − 2 .
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Two things i want to mention 1. Mention g = 10 m/sec^2 to avoid confusion because thats only an approximation
My next question is to you @Ramon Vicente Marquez
What will be the normal reaction between block A and vertical wall be doing?
The normal force between A and the vertical wall has to be zero. If this force were not zero, then there must be a force that pushes A towards the vertical wall.
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Wait i think system is going to left isn't it?
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the only way for the system to move from the given initial position shown in the figure is if A moves to the left
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@Ramon Vicente Marquez – Yeah then Why would the Normal reaction will be zero? . Block A Will loose contact Immediately from the wall right?
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@Prakhar Bindal – Yes. Normal force is zero since A loses contact with the wall.
Ohhh but my method was exactly the same,lemme check my solution!
Even though my method was the exact same,in the end I got 9g/28.Which I approximated to 3.Is this right? @Ramon Vicente Marquez
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That was just a coinicidence . i solved got exact 3g/10
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I got my mistake!One minus can make one heluva difference :P.
9 g / 28 is wrong. the exact answer is 0.3 g. check your math.
@Prakhar Bindal
There would be no normal reaction between A and vertical wall because A is just touching the wall.
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N sin x = (9/64)mA
2mg - T - N cos x = 2mB
2T - mg = mC
A tan x = B = 2C
C = 0.3 g