182 sweets are equally divided among a certain number of children at a party. If the number of sweets each child receives is one more than the number of children, find the number of children at the party.
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I use the same method
They were integers, so I guessed-and-checked.
A simple multiplication will be enough to get the answer:
1 3 × 1 4 = 1 8 2
But that would mean that you're testing values one by one until you get it
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Yes I was testing the values but not one by one.
The number of candies given to a child is one greater than the number of children.
So that means ( n ) × ( n + 1 ) = 1 8 2 .
Now think of the two numbers with this result.
It is obvious that, they cannot be greater than 15 as 15×16=240.
And cannot be less than 10 as 10×11=121.
This can be applied for smaller numbers, but for larger numbers we will have to go through the conventional way only(like you did).
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There is one more method, just factorise 182.
1 8 2 ⇒ 1 3 × 7 × 2 ⇒ 1 3 × 1 4
There we get our answer!
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@Yash Jain – Yes, this looks good. :)
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@Abhay Tiwari – Kinda similarly I checked integers, but to narrow the field, i took the sqrt(182) and got 13.5, so the first numbers I checked were 13 and 14 and it worked!
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@Connor Jennison – Ya, this is good too, gets you the idea for the values, good one :)
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Let the number of children be x . The number of candy each child gets is x + 1
Therefore, we have the equation:
x 1 8 2 = x + 1 1 8 2 = x ( x + 1 ) x 2 + x − 1 8 2 = 0 ( x + 1 4 ) ( x − 1 3 ) = 0 x = − 1 4 , 1 3
Since we know that x > 0 , the number of children is x = 1 3