Ques. -10

"A" draws two cards at random from a pack of 52 52 cards. After returning them to the pack and shuffling it, "B" draws two cards at random. The probability that their draws contain exactly one common card is :

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25 546 \frac{25}{546} 100 663 \frac{100}{663} 25 663 \frac{25}{663} 50 663 \frac{50}{663}

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2 solutions

Vighnesh Raut
Mar 2, 2015

The probability that no card is same is

( 50 2 ) ( 52 2 ) = 25 × 49 26 × 51 \displaystyle{\frac { \left( \begin{matrix} 50 \\ 2 \end{matrix} \right) }{ \left( \begin{matrix} 52 \\ 2 \end{matrix} \right) } =\frac { 25\times 49 }{ 26\times 51 } }

The probability that both cards are same is

1 ( 52 2 ) = 1 26 × 51 \displaystyle{\frac { 1 }{ \left( \begin{matrix} 52 \\ 2 \end{matrix} \right) } =\frac { 1 }{ 26\times 51 } }

Hence, the probability that exactly one card is common is

= 1 25 × 49 26 × 51 1 26 × 51 = 50 663 \displaystyle{=1-\frac { 25\times 49 }{ 26\times 51 } -\frac { 1 }{ 26\times 51 } =\frac { 50 }{ 663 }}

Cody Martin
Feb 26, 2015

( 52 1 ) ( 51 2 ) 2 ! ( 52 2 ) ( 52 2 ) = 50 663 \frac{ \left(\begin{matrix}52 \\ 1\end{matrix}\right)*\left(\begin{matrix}51 \\ 2\end{matrix}\right)*2! }{ \left(\begin{matrix}52 \\ 2\end {matrix}\right) *\left(\begin{matrix}52 \\ 2\end{matrix}\right)}=\frac{ 50 }{ 663 }

Can you please explain your answer ?

Arpit Agarwal - 6 years, 3 months ago

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sure... from first 52 cards choose a card in common in 52C1 ways now 2 cards for both of them can be anything but not same which is just 51P2 ways and total sample space can be 52C2*52C2 ( 2 cards each to be drawn from pack by both A and B) if any doubt left please tell..

Cody Martin - 6 years, 3 months ago

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@Arpit Agarwal

Cody Martin - 6 years, 3 months ago

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@Cody Martin Thanks a lot Cody :) I guess I kinda overthinked for this question

Arpit Agarwal - 6 years, 3 months ago

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