"A" draws two cards at random from a pack of 5 2 cards. After returning them to the pack and shuffling it, "B" draws two cards at random. The probability that their draws contain exactly one common card is :
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( 5 2 2 ) ∗ ( 5 2 2 ) ( 5 2 1 ) ∗ ( 5 1 2 ) ∗ 2 ! = 6 6 3 5 0
Can you please explain your answer ?
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sure... from first 52 cards choose a card in common in 52C1 ways now 2 cards for both of them can be anything but not same which is just 51P2 ways and total sample space can be 52C2*52C2 ( 2 cards each to be drawn from pack by both A and B) if any doubt left please tell..
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@Cody Martin – Thanks a lot Cody :) I guess I kinda overthinked for this question
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The probability that no card is same is
( 5 2 2 ) ( 5 0 2 ) = 2 6 × 5 1 2 5 × 4 9
The probability that both cards are same is
( 5 2 2 ) 1 = 2 6 × 5 1 1
Hence, the probability that exactly one card is common is
= 1 − 2 6 × 5 1 2 5 × 4 9 − 2 6 × 5 1 1 = 6 6 3 5 0