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If the figure in the left is named figure 1, the one in the middle is named figure 2 and the one in the right is named figure 3, then find the number of triangles in the 2016 th {2016}^{\text{th}} figure that follows this sequence.


The answer is 4070307.

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1 solution

Ashish Menon
Apr 20, 2016

The number of triangles in n th {n}^{\text{th}} case is given by the formula:-
( 2 × i = 0 n + 1 i ) + 1 (2× \displaystyle \sum_{i=0}^{n + 1} i) + 1

So, in the 2016 th {2016}^{\text{th}} figure there would be ( 2 × i = 0 2017 i ) + 1 (2× \displaystyle \sum_{i=0}^{2017} i) + 1 triangles.
=4070307 triangles. _\square

7 + n 2 ( 6 + ( n 1 ) 2 ) 7 + \frac{n}{2}(6 + (n-1) 2)

This will also get the answer, here n = 2015 n=2015 .

Abhay Tiwari - 5 years, 1 month ago

Ashish, Click HERE

Abhay Tiwari - 5 years, 1 month ago

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Hi, I am just back, nice question, I see that you started using GeoGebra ;)

Ashish Menon - 5 years, 1 month ago

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Ha ha, all credit goes to you :)

Abhay Tiwari - 5 years, 1 month ago

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@Abhay Tiwari Thanks! ;) Your problem was fun solving

Ashish Menon - 5 years, 1 month ago

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