Reducing Numbers

Gabriel play with numbers with two or more digits. He replaces the 2 left-most digits of the number by their sum and repeats this process until he gets a single-digit number.

For example, starting with the number 2018 2018 he gets: 2018 218 38 11 2 2018 \rightarrow 218 \rightarrow 38 \rightarrow 11 \rightarrow 2

How many 3-digits numbers will result in the number 1 1 doing the process shown above?

Problem from Brazilian Math Olympiad of Public Schools.

10 56 100 9 80

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1 solution

The recursive process, applied to an integer, is equivalent to finding the original number modulo 9 9 . Therefore we need to find x x that satisfy x 1 ( m o d 9 ) x\equiv 1 \ (mod \ 9) and are in the range 100 x 999 100 \leq x \leq 999 .

100 x 999 100 9 k + 1 999 11 k 110 100 \leq x \leq 999 \implies 100 \leq 9k+1 \leq 999 \implies 11 \leq k \leq 110

so, there would be 110 11 + 1 = 100 110-11+1= 100 of such three digit integers.

What would be the first step if you had 395? Would you have 125?

Joshua Lowrance - 2 years, 6 months ago

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yes, why? I think you are about to put me in trouble :)

A Former Brilliant Member - 2 years, 6 months ago

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No, I am not. ;) I just forgot to account for those numbers when I did the problem. Thanks for clarifying!

Joshua Lowrance - 2 years, 6 months ago

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@Joshua Lowrance No worries man.

A Former Brilliant Member - 2 years, 6 months ago

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