− A D B B C D C B A D A C
The above shows a cryptarithm such that each letter represents a distinct digit.
Calculate the 4-digit integer, B D A C .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Can u explain the step following 989A-1099D = 910B+91C = 91(10B+C) clearly, I didn't understand how we got the values of A and D
Log in to reply
It's called modular operation. For example, when you divide 1099 with 91, you get a remainder of 7, so 1099 = 7 (mod 91). Then we can treat such congruence as one kind of equations on the same modulus used, 91 in this case.
Do you know the speciality of that four digit number 6174 it's kaprekar number
Log in to reply
Oh, unfortunately I don't. What does it mean?
Log in to reply
Kaprekar is a mathematics teacher in a primary school in India during 20th century and
First consider any four digit nums except nums as 9999 8888 7777 etc
For eg : Consider 1234.
Now arrange it in descending order and subtract with it's ascending order
4321-1234=3087
Similarly 8730-0378=8352
8532-2358=6174
7641-1467=6174
7641-1467=6174
Similarly you can do this for any four digit number except those on top.
Log in to reply
@Hemanth Koundinya – Nice!!! How would u guys know all these, I am of X standard but what is the min standard to get a grip on all these? And what's ur age
Log in to reply
@Suneel Kumar – My age is 18 I'm a b tech student in Karnataka.actually there is no minimum standard or age to know all these please keep on surfing about mathematical achievements by Indians that's all required
Log in to reply
@Hemanth Koundinya – Rolle's theorem is given by bhaskara charya 2 in 5th century
Problem Loading...
Note Loading...
Set Loading...
1000A+100B+10C+D -(1000D+100C+10B+A) = 1000B+100D+10A+C
989A-1099D = 910B+91C = 91(10B+C)
989 = -12 (mod 91); 1099 = 7 (mod 91)
So 12A+7D = 0 (mod 91).
91= 1 3 × 7 = 1 2 × 7 +7.
So A=7; D=1.
Then 91(10B+C) = 9 8 9 × 7 -1099 = 5824. 10B+C = 64; B=6; C=4.
Thus, the answer is 6174.