Rising Factorial (Problem 1 1 )

Algebra Level 2

10 0 ( 4 ) = 100^{(4)} =

Hint: x ( n ) x^{(n)} denotes the rising factorial

For more information about rising and falling factorials, check out the Wikipedia article .


The answer is 106110600.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

By definition, for positive integers m m and n n ,

m ( n ) = ( m + n 1 ) ! ( m 1 ) ! m^{(n) }=\dfrac {(m+n-1)!}{(m-1)!}

So 10 0 ( 4 ) = 103 ! 99 ! = 106110600 100^{(4)}=\dfrac {103!}{99!}=\boxed {106110600} .

Nice! You know that mine is simpler, though, by using x ( 4 ) x^{(4)} and substituting x = 100 x = 100 ? @Alak Bhattacharya

Yajat Shamji - 11 months ago

Log in to reply

For this particular problem only. How will you do with 10 0 ( 50 ) 100^{(50)} , or to be worse, 99 9 ( 199 ) 999^{(199)} ?

Log in to reply

You can't do anything over x ( 7 ) x^{(7)} when x 100 x \geq 100 .

Yajat Shamji - 11 months ago

Log in to reply

@Yajat Shamji Why? Does the definition break down for those values?!!

Log in to reply

@A Former Brilliant Member No calculator can calculate beyond it. For the human mind, this may as well be the limit.

Yajat Shamji - 11 months ago
Yajat Shamji
Jul 14, 2020

10 0 ( 4 ) = 100 ( 101 ) ( 102 ) ( 103 ) = 106110600 100^{(4)} = 100(101)(102)(103) = \fbox{106110600}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...