If π can be expressed as continued fraction, then what is the number which is surely less than or equal to the AM of all the numbers(except 1) in the continued fraction form?
Note: Give your answer to at least 2 decimals.
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You need to fix your question, and change "AM" to "GM", that is, not arithmetic mean, but geometrical mean.
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But through AM-GM inequality,
AM is greater than or equal to GM
And that's what I have written, number which is surely less than or equal to AM.
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The question implicitly asks for the "largest number", since otherwise it would allow for infinitely many answers.
As Michael pointed out, you have only shown that the GM is bounded (by 2.68 in most cases), but have not established that the AM must also be bounded by 2.68. This seems somewhat unlikely.
How do you know that the answer cannot be 2.69 or anything higher?
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@Calvin Lin – Sir, I have edited the problem and now it says that "the number which is surely less than or equal to the AM." I hope now this is correct and if not, I will make it GM. Please reply me on this context!
I checked out google there is nothing called Kitchinnie's constant.
@Calvin Lin Can you make a note on Kitchinnie's constant explaining it in depth?
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Pinak Wadikar Actually,he has misspelled it.The correct name is Khinchin‘s Constant .You can read about it here
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This is just a Kitchinnie's constant problem
Largest number which is less than or equal to the AM of all numbers(AM-GM inequality)
Therefore, we get the answer as Kitchinnie's constant = 2.6853....
P.S. - Kitchinnie founded that for most real numbers x,
which can be expressed as
x = a 0 + a 0 + a 1 + a 2 + a 3 + . . . . . 1 1 1
( a 0 a 1 a 2 . . . . . . ) 1 / n as tend to infinity = Kitchinnie's constant = 2.68....