Simple. (Problem 7 )
( 2 x ) ! = ( x + 1 ) !
Find x where x = 0
Tip: If you want to, you can remove the ! sign.
The answer is 1.
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1 solution
Your answer is correct but the method is wrong because of 2 × x ! = ( 2 x ) !
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( 2 × x ) ! = ( 2 x ) !
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@Yajat Shamji – What you are saying isn't wrong! But your solution is wrong. In the problem, you have written 2 × x ! but in the solution, you write it as ( 2 x ) ! . And i am saying that the two aren't equal, the answer is same but it isn't applicable for any x
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@Mahdi Raza – Look above now. Happy?
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@Yajat Shamji – But if you have parentheses, x=0 is a valid answer.
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@Ved Pradhan – Oh yes, the question changes the answer, and now they are 1 and 0, never mind. I don't want to bang my head into the wall. I still repeat it!:
2 × ( x ) ! = ( 2 x ) !
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@Mahdi Raza – Look above again.
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@Yajat Shamji – Great! I would still suggest adding brackets 2 x ! ⟹ ( 2 x ) ! and ask what is the sum of values of x . The answer will still remain 1 + 0 = 1 . Thanks for adding it!
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@Mahdi Raza – Look now. But I am not asking for the sum of values of x .
( 2 x ) ! = ( x + 1 ) !
Remove the factorial sign:
2 x = x + 1
2 x − x = 1
x = 1