3 0 4 + 1 2 0 4 + 2 7 2 4 + 3 1 5 4 = a 4
Find the positive value of a .
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Nice. calculator used
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Not really, these kind of problems can be solved using hand, but it takes about 5 - 10 mins to do so. Its kind of a brute force method, with trying to guess the hundreds digit and all.
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It was a guess,btw upvoted+1
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@Srijan Singh – Bad guess then. Even 12 year olds in my school can solve this. What about you? How'd you solve this?
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@A Former Brilliant Member – same method
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@Srijan Singh – Then you are basically insulting me by guessing that I used calculator. The guy who can't speak in English without twisting his tongue thinks I can't solve a problem a simple problem by hand. Oh the irony!
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@A Former Brilliant Member – Bro why do you take everything serious ...I made a guess
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@Srijan Singh – lol I am just making an ironic statement, nothing too serious about it. YOu really need to learn english kid @SRIJAN Singh
@Percy Jackson , Indeed calculation was doable.But,I was not expecting such solution (at least not from you).
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1) 'Doable' isn't a word.
2) It was the fastest thing I could think of, because I was kind of in a hurry. I'll change it when I have time. Also, I am busy updating my pseudo-wiki/note on Tau, so I am busy even when I'm on Brilliant.
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1.You need to improve your English. Have a look.
2.I won't comment on it.
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@A Former Brilliant Member – 1) Sorry, let me rephrase - "You have incorrectly phrased your sentence with the very existing word, doable". Anyway, who cares, coz we use slang while typing all the time. English doesn't really matter that much.
2) ok
Is there a non-brute force solution to this? To be honest, brute force isn't interesting to me, whether done by hand or using a calculator.
I just remembered that this is one of the sets of numbers in the Lander, Parkin and Sellfridge Conjecture where k(the exponent) = 4. It was formed in the process of disproving Euler's conjectures about the sum of powers and stuff. @Kriti Kamal
Link to the Lander Parkin Selfridge Conjecture
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Nice wiki!
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Yup (some text)
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@A Former Brilliant Member – I think it's 4:23 in America and you haven't slept yet
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@Srijan Singh – Its 12 AM in Alaska. We have a different time zone, so...
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@A Former Brilliant Member – Oh okay If I was there in your place I would slept at 10:00
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@Srijan Singh – I sleep at 1:00 or 1:30 sometimes, I'm mostly up studying. I have a lot to finish.
@Percy Jackson have a look at this
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3 0 4 = 3 0 × 3 0 × 3 0 × 3 0 = 8 1 0 0 0 0 1 2 0 4 = 1 2 0 × 1 2 0 × 1 2 0 × 1 2 0 = 2 0 7 3 6 0 0 0 0 2 7 2 4 = 2 7 2 × 2 7 2 × 2 7 2 × 2 7 2 = 5 4 7 3 6 3 2 2 5 6 3 1 5 4 = 3 1 5 × 3 1 5 × 3 1 5 × 3 1 5 = 9 8 4 5 6 0 0 6 2 5 8 1 0 0 0 0 + 2 0 7 3 6 0 0 0 0 + 5 4 7 3 6 3 2 2 5 6 + 9 8 4 5 6 0 0 6 2 5 = 1 5 5 2 7 4 0 2 8 8 1 4 1 5 5 2 7 4 0 2 8 8 1 = 3 5 3
(For all you people like @SRIJAN Singh who think I used calculator, I didn't. This is a very easy problem that can be solved by hand, so don't bother annoying me like Srijian did)
This set of numbers raised to the 4th power is actually one of the sets in the Landen, Parkin, Selfridge Conjecture . You can understand more about it in the link, but it was formed in the process of disproving Euler's identity's like the Euler quartet conjecture.