Flowery Union
In a club of 40 executives (all of whom like flowers), 33 like Red Roses and 20 like Black Roses. How many like both?
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4 solutions
Wonderful! I liked what you've done here especially with the text colors in the diagram. Keep it up!
Wow, the question has been changed from cigarettes to flowers. More kid-friendly, I guess.
Now, let the number of executives who like both be x .
The number of executives who like Red Roses only = 3 3 − x
The number of executives who like Black Roses only = 2 0 − x
The number of executives who do not like flowers = 0
These four numbers add up to 4 0 :
x + ( 3 3 − x ) + ( 2 0 − x ) + 0 = 4 0 5 3 − x = 4 0 x = 5 3 − 4 0 = 1 3
You can use a Venn diagram to illustrate this. Try it yourself!
Yes, ofcourse flowers are more kid friendly. Nice algebraic approach. And yes venn diagrams would be nice so I added a solution. (+1)
(33-x)+(20-x)+x=40 thus x=13
You should say that N o b o d y d o e s n ′ t l i k e a n y o f i t
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Thanks @Pham Khanh for the nice suggestion. It has been updated. :)
Can you make your solution more detailed so that others can understand it? Thanks :)
BTW, nice problem.
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the value of x is equal to 13 50+13=63 63-40=13
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You haven't mentioned what x represents. And how is x equal to those values?
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@Sandeep Bhardwaj – let the x be the number of executives who like both...slow learner..haha
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@Lorenz Navales – haha. thanks for explaining this. Could you please update this in your solution?
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@Sandeep Bhardwaj – of course haha. by the way nice suggestion thank you very much...
@Sandeep Bhardwaj – Naughty staff XD
Lets draw a venn diagram and evaluate. The number of people who like red roses only = total number of people - people liking black roses = ( 4 0 − 2 0 = 2 0 ) and thise liking black roses only = total people - people liking red roses = ( 4 0 − 3 3 = 7 ) . So those who love both = 4 0 − ( 2 0 + 7 ) = 1 3 . Everyone loves a flower so the universal set does not contain those who love neither the flowers.
