$\large \textsf{Points to remeber} \Rightarrow$

• All angles of an equilateral triangle equal $60^{\circ}$

• All three sectors are identical, as all of them have a $60^{\circ}$ angle and equal radii lengths.

• Radius length of all three sectors is half of the triangle's side length $= \frac{7}{2} = 3.5$

• $60^{\circ} = 1.0472\ldots \ Radians$

• Area of curvier triangle = Area of equilateral triangle - Area of 3 sectors

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$\large \textit{SOLUTION} \Rightarrow$

$\begin{aligned} Area \ of \ equilateral \ triangle \ &= \ \dfrac{\sqrt{3}}{4} \times \ side^{2} \\ &= \dfrac{\sqrt{3}}{4} \times 7^{2} \\ &= \dfrac{49 \sqrt{3}}{4} \\ &\approx 21.22\end{aligned}$

.

$\begin{aligned} Area \ of \ 3 \ sectors \ &= \ 3 \times \ Area \ of \ a \ sector \ (As \ all \ sectors \ are \ identical) \\ &= 3 \times \dfrac{radius^{2} \times \ angle}{2} \\ &= \dfrac{3 \times 3.5^{2} \times 1.0472 \ Radians}{2} \\ &\approx 19.24\end{aligned}$

.

$\begin{aligned} Area \ of \ curvier \ triangle \ &= \ Area \ of \ equilateral \ triangle \ - \ Area \ of \ 3 \ sectors \\ &= 21.22 - 19.24 \\ &\approx \boxed{\underline{1.97}}\end{aligned}$

@Yajat Shamji

@Percy Jackson