Decode These Python Strings

Technically it will print an error because neither sequence is defined as a string.

In any case, so long as that fixed, != means not equal to, so the function compares the ith character in each sequences and counts the number of differing pairs.

The formula is a for loop in Python that checks each character in both strings to see if there is a difference between the characters in the two strings.

It will add +1 to the count every time there is such a difference.

i=0: T and H differ

i=1: h and e differ

i=2: i and r differ

i=3: s and e differ

i=13: O and I differ

i=14: f and n differ

Therefore, because there are 6 characters that differ, printing count will yield 6.

the difference between two string is 'here' and 'in' and the number of characters in this two words is 6 therefor answer is 6

As length of sequence 1 is 19. So loop will executed 20 times as it started with a value of 0 for i. Now if character of both sequence 1 and sequence_2 at same position matches, if condition will execute and increase count value with 1. As we can see, for only 6 character if condition set to true. So count value will be 6

Here we have two strings. They can also be described as an array of characters, which is what the problem is about. The for loop loops through the first string's length (identical to the length of the second string) and compares each character in the two strings. If they differ, then count is incremented, if not, nothing happens.

From there, we see that the two strings only differ at 6 points ("This" and "Here", and "Of" and "In") telling us that there are six places where the strings are different. Therefore, the answer is 6.

I read through the code. It simply prints out the number of letters in sequence_1 that are different from the corresponding letters in sequence_2 . It compares char 1 of sequence_1 to char 1 of sequence_2 , char 2 to char 2, char 3 to char 3, etc.

Once I knew this, and since the values have been so nicely formated for me (thanks!), I simply counted the corresponding letters.

I must raise my hand in protest, however. The program will not print this out, as it currently stands. The reason is that there are 4 syntax errors that should be fixed before it runs. You see, it is missing a double quote before and after every literal string. (sequence 1 and sequence 2). As it is, Python just chockes and dies in error.

len(sequence 1) is 18. count=0. The number of different characters in sequence 1=count. Here 6 characters are different in both the strings... i.e, "This" and "here" 4 characters are different , "of" and "In" are different 2 characters. Totally 6 characters are different. Count increases to 6. So answer is 6.

Simple string comparison letter by letter:

T != H h != e i != r s != e I == I s == s and so on

There are six letters that do not match up by position, each of which increments the count variable by one: This/Here (Positions 0 to 4) and Of/In (Positions 12 to 13)

In this program, we see that both strings have same lengths. count=0 at first. The "for loop" with i as counter variable runs from i=0 to i=String length. In the "if loop", we see that it is checked that the characters of the same position in both strings are equal or not. If not equal, count variable is incremented. The first 4 letters of both strings satisfy the condition as each letter of one string is different from the character in that position of the other string. So, count becomes 4 at the end of checking the 4th position characters with i=3. After that, strings are having same letters in corresponding positions so the condition is now false. Then at the time of checking of the parts "Of" and "In" of the strings, the condition is again fulfilled and count increments to 5 and then 6. The rest of the string does not satisfy the condition and thus count is not further incremented. So, count=6 at end and "print count" prints the value of count $=\boxed{6}$

If it works correctly without any error than output of count value is 6

i know it's 6 but i wrote the same code in C++ to be assured:

string s1 = "ThisIsAStringOfCode";
string s2 = "HereIsAStringInCode";

int numb = 0;

for ( int i=0; i<s1.size(); i++)
    if (s1[i] != s2[i])
        numb++;
cout << numb;

cout << endl;
return 0;

It will compare each character in the first string with the second Then it will increment the count of non-matching characters which, in this case is 6

I don't learn pyhton but after reading the code i'm getting interesting in python

I am not bothered about syntax errors, I compiled with my brain. This problem is comparing the two strings, if the letter in string does not match count will increase, as "Here" and "In" are not matching answer is 6

here, len(sequence 1)=19 so the loop execute between 0-18 on the execution of loop each and every time sequence 1 compare to sequence_2 on comparison if they are not similar then count and increment by 1.

ThisIsAStringOfCode HereIsAStringInCode

here, sequence 1[0] != sequence 2[0] (t!=h) so count=0; sequence 1[1] != sequence 2[1] (h!=e) so count=1;

this execution will repeat until i becomes 18.

after execution of loop we get count=5; after looping count becomes count+1; so count=5+1=6

In this code , the value of count is incremented every time whenever the character of sequence 1 matches the character of sequence 2 As there are 6 characters which are same in both the strings so the answer is 6.

its 6 !!!

because it counts different letters..

Length Of String 1 and 2 is same There is going in traversing of string so each different letter at same index will result in couter++

Here the code counts non-matching letters of the 2 strings. The for loop iterates the for the length of the string (2 strings have same length) and the If condition within for loop checks whether each character in the 2 strings does not match each other , then the count is increased

the answer must be 6

Simple Math.

This is fairly simple. The code looks at the first letter of each string, then the second letter and so on. Every time the two letters are different 1is added to count. This happens six times, so the answer is six.

The program just counts dissimilar characters in both the strings.

In this case, count will be incremented when char sequence was different, then, this program willcount how many different characters in each string; In this case is 6.