Squigi Boo Saves Riji Boo!

each timeSquigi Boo jups 04 meters but falls 01 meters, so the net gain is 03 meters.In 32 attempts he climbs 96 meters. when jumps now he jumps 04 meters and reaches top of wall ie 96+4=100 meters

$4-1=3,$ $\frac{96}{3}=32,$ $100-96=4,$ $32+1=\boxed{33}$

$\frac{100}{(4-1)} = 33$

Dudes!! If he jumps 33 times he only reaches the 99 meters... 4-1=3 3x33 = 99

Check your answer before posting ;)

at last jump there is no way he gonna slid back back because he will be already out so jump = 4, per jump+slide = 3, 100-4=96, 96/3 =32, 32 +1 = 33 jumps

I first got the number of meters he reaches with every jump=3 meters. I already knew that 3 goes into 100 (meters of the well) 33 times. Since after he reaches the top of the well he can't fall back down, I tried 33. Hopefully this was helpful (no offence to the geniuses who use calculations..its kind of hard to understand...)

Let the number of jumps be n. Thus 4n-n =99 (Because he falls bu 1m at last) Thus n = 33

What I did was 4-1 since he jumped up 4 then fell 1. After that simply divide by 100. Although it should be 34 since 100/3 = 33 with remainder 1 so he's not fully up therefore it should be 34

If he fell every 4 meter, that means, he would just able to climb 3 meters in each trial. To get thru 100 meters, he need 33 jump, to get 99 meter. Since each climb he get 3 meter, he had spared 2 meter in fact.

100/(4-1) = 33

4 meters up & 1 meters down that's mean 3 meters up!!

100/3 = 33.33

answer is 33.

3x=96 or,x=32 again,4y=4 or,y=1 so,x+y=32+1=33

100/(4-1)=33

32 attempts + final attempt (32 x3) + 4 = 100 So they will out after 33 Attempts

He jumps up 4 meters and falls down one meter so this means he is jumping 4-1=3 metres upwards in one try so number of jumps required= 100/3=33.3 or 33 :)

given: 100meters. rate: 4m per 1 jump. for every 4meter there's -1m. 3m/jump or 1jump/3m solution: 100m x(jump/3m) = 33.33jumps approximately 33jumps.

firstly Boo holds 4-1=3m , secondly 3m too , ........ so on 32 times and reach 96m. but at last hold Boo recovers the all distance by ascending last 4m ,i maen Boo comes out from well. so Boo do not fall 1m down at last.

given : depth of well=100m squigi boo's one jump=4m,but falls 1m therefore his one jump = 4m-1m=3m number of jumps= 100/3=33.33.......=33 jumps (approx.)

see.... when it jumps 32 times it reaches 96m (u cn solve it by simply dividing it by 3,,, 96/3 =32) so nw it wll jump 1 mr time so its out so 32+1=33 jumps... 96+4=100m

Squigi Boo jumps 4 meter up with riji boo but fall 1 meter so 4-1= 3 meter. as well is 100 meter deep so total jumps will be 100/3 = 33.33 approx. 33 jumps.