Stop or Go

Geometry Level 2

In this regular octagon, which triangle has the greater area?

The red triangle The green triangle They are both equal

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2 solutions

Saya Suka
Mar 15, 2021

If we rotate the octagon 22.5° clockwise, both the red and green triangles will have their bases parallel horizontally. Then, it's easier seen with all the parallel lines that the green triangle is similar to the larger obtuse triangle where the red lies inside, sharing its base (spanning from one octagonal vertex to another) and its peak (highest vertex). Once the picture is seen, we can mentally slide and push the green triangle along the two parallel lines up until the green's peak meet the red's peak (which is also the octagon's center). Done with the upwards translation, we start a rotation of 90° of either direction. The triangles will produce a 180° base together (we can already see this at the end of the previous translation with red's peak taking one angle of 45° –as clearly from the word octagon– and noting that the green's peak occupying 3 times of the red's peak angle) and the new triangle formed by them has twice the base length and the same height.

@Saya Suka What’s after this, I couldn’t understand

Jason Gomez - 2 months, 4 weeks ago

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Rotate just the greenie around center

Saya Suka - 2 months, 4 weeks ago

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Thanks got it

This is the final figure right

Jason Gomez - 2 months, 4 weeks ago

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@Jason Gomez Thank you for this visual, Jason! The 1-hour soap opera just ended, lunch is more delicious with more drama, sorry I can't express my appreciation faster. Thanks again! 👏👍💪🏼🤗💖

Saya Suka - 2 months, 4 weeks ago

I can see everything required from this picture, I assume the part of the explanation which confused me a lot was the 18 0 0 180^0 base part (still have no clue on what that meant)

Jason Gomez - 2 months, 4 weeks ago

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@Jason Gomez Red's 45° + Green's 135° = 180° as the base of newly created double area right triangle.

Saya Suka - 2 months, 4 weeks ago

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@Saya Suka Oh, now I understand everything

Jason Gomez - 2 months, 4 weeks ago

@Jason Gomez Easier to see their equality with shared height and side-by-side half base.

Saya Suka - 2 months, 4 weeks ago

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@Saya Suka I can see it now in both ways, was quite blind before

Jason Gomez - 2 months, 4 weeks ago

What do you use to make images and stuff? Look really cool :)

A Former Brilliant Member - 2 months, 4 weeks ago

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I use notability (about 10$) on my iPad

Jason Gomez - 2 months, 4 weeks ago

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@Jason Gomez I use this device to take down class notes and other educational stuff, so that’s the reason I bought this app (Notes is just too bad)

Jason Gomez - 2 months, 4 weeks ago

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@Jason Gomez True facts, default note-taking apps suck...

A Former Brilliant Member - 2 months, 4 weeks ago

@Jason Gomez Oh, nice. I guessed it would be Notability, saw the similarity with Andrew Last's solutions.

A Former Brilliant Member - 2 months, 4 weeks ago

Simple approach - sin(3pi/7)=sin(pi/7).

Yuriy Kazakov - 2 months, 3 weeks ago

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Same sines, and then what? How do I know if the sides are the same without a compass? 1/4 = 3/4, right?

Saya Suka - 2 months, 3 weeks ago

Where did you get the π 7 \frac{π}{7} I can only get the angles in multiples of π 16 \frac{π}{16}

Jason Gomez - 2 months, 3 weeks ago

Two Sides of green triangle and two Sides of red triangle - equal.

Yuriy Kazakov - 2 months, 3 weeks ago

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Any proof of that?

Saya Suka - 2 months, 3 weeks ago

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Simple exercise for students

Yuriy Kazakov - 2 months, 3 weeks ago

@Saya Suka Could you help me in this problem , I think I am close to the solution but at the same time feel very far away

Jason Gomez - 2 months, 3 weeks ago

Excuse my mistake - sin(2pi/8)=sin(3 2pi/8), and green and red areas equal a a * sin(2pi/8)/2

Yuriy Kazakov - 2 months, 3 weeks ago

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Still incorrect, as I said earlier, 1/4 vs 3/4.

Saya Suka - 2 months, 3 weeks ago
Jason Gomez
Mar 15, 2021

Just as Percy said

They are always equal

Not exact quote but close enough \tiny\text{Not exact quote but close enough}

I have no clue how to solve this and it seems a little too monstrous to try

lol @Jason Gomez

I did the same thing... \tiny \text{I did the same thing...}

A Former Brilliant Member - 2 months, 4 weeks ago

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