Strange hexagon

Find the number of triangles (excluding degenerate triangles) in the given figure.

In the given figure, V T R 1 S 1 H 1 J VTR_1S_1H_1J is a hexagon, such that :-

There are 19 19 defined points on T J TJ (excluding T T and J J ) which are connected to V V and O O (the geometric center of the hexagon) by line segments such that V V is on opposite side of T J TJ as compared to O O .

Similarly, there are 19 19 defined points on R 1 H 1 R_1H_1 (excluding R 1 R_1 and H 1 H_1 ) which are connected to S 1 S_1 and O O (the geometric center of the hexagon) by line segments such that S 1 S_1 is on opposite side of R 1 H 1 R_1H_1 as compared to O O .

There are 19 19 defined points on T R 1 TR_1 (excluding T T and R 1 R_1 ) which are connected to O O by line segments such that T R 1 TR_1 is on opppsite side of O O as compared to J H 1 JH_1 .

There are 19 19 defined points on J H 1 JH_1 (excluding J J and H 1 H_1 ) which are connected to O O by line segments such that T R 1 TR_1 is on opppsite side of O O as compared to J H 1 JH_1 .

Please zoom in if the image is small to see.


The answer is 1304.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Ashish Menon
Apr 2, 2016

In triangle V T J VTJ , there are 210 210 triangles. Similarly, R 1 H 1 S 1 , R 1 O H 1 , J O H 1 , J O T , T O R 1 R_1H_1S_1 , R_1OH_1, JOH_1,JOT, TOR_1 have 210 210 triangles.

Now, in triangle in O R 1 S 1 OR_1S_1 , there 10 10 triangles. In this counting I have excluded the individual triangles which I counted in previous procedure.
Now, we see that O S 1 H 1 , V J O , V T O OS_1H_1 , VJO , VTO are exactly the same like O R 1 S 1 OR_1S_1 , so each of them have 10 10 triangles .

Now in square T R 1 H 1 J TR_1H_1J , there are 4 4 triangles namely, T J R 1 , T J H 1 , T R 1 J , J H 1 R 1 TJR_1 , TJH_1 , TR_1J , JH_1R_1 .

So, the total number of triangles are ( 210 × 6 ) + ( 10 × 4 ) + 4 = 1304 (210 × 6) + (10 × 4) + 4 = \boxed{1304} triangles.

Why is it 310? Am I missing something? If it needs to be non-degenerate it should include V, so there would be ( 21 2 ) = 210 \binom{21}{2}=210 ways of getting triangles from the remaining points.

Vishnu Bhagyanath - 5 years, 2 months ago

Log in to reply

@Ashish Siva

Vishnu Bhagyanath - 5 years, 2 months ago

Log in to reply

Nothing wrong, its my bad, I will get ir fixed, thank you :-). I took 310 instead of 210

Ashish Menon - 5 years, 2 months ago

Log in to reply

@Ashish Menon It's been much longer than 15 minutes, care to explain why it is 310?

Vishnu Bhagyanath - 5 years, 2 months ago

Log in to reply

@Vishnu Bhagyanath Sorry again, I am wrong

Ashish Menon - 5 years, 2 months ago

Log in to reply

@Ashish Menon I initially intended something else

Ashish Menon - 5 years, 2 months ago

thank you sir

Rohit Nandwani - 1 year, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...